Question

How do you solve this?-2x+8=3x+14thanks

Answer 1

Given:

$-2x+8=3x+14$

Our goal is to isolate x on one side of the variable with no coefficient. Let's begin. First, let's get subtract 3x from both sides to cancel the +3x on the right. We are then left with:

$-5x+8=14$

Next, subtract 8 from both sides to cancel the +8 on the right. This isolates x on the left side. When we do that, we get:

$-5x=6$

Since we are solving for x, x cannot have a coefficient. To remove the coefficient, divide both sides by the coefficient, which is -5.

$\frac{-5x}{-5}=\frac{6}{-5}$

Simplify.

$x=-\frac{6}{5}$

Answer 2

Question: -2x + 8 = 3x + 14

Steps:

1. Subtract 3x from both sides

-2x - 3x + 8 = 3x - 3x + 14

2. Simplify:

-5x + 8 = 14

3. Then, subtract 8 from both sides:

-5x + 8 - 8 = 14 - 8

4. Simplify,

-5x = 6

5. Then, divide both sides by -5

-5x/-5 = 6/-5

6. Simplify,

x = -6/5 <--------------- Answer

Hope this helped!!!!