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Allushta [10]
3 years ago
9

How do you solve this?-2x+8=3x+14thanks

Mathematics
2 answers:
kobusy [5.1K]3 years ago
7 0

Given:

-2x+8=3x+14

Our goal is to isolate x on one side of the variable with no coefficient. Let's begin. First, let's get subtract 3x from both sides to cancel the +3x on the right. We are then left with:

-5x+8=14

Next, subtract 8 from both sides to cancel the +8 on the right. This isolates x on the left side. When we do that, we get:

-5x=6

Since we are solving for x, x cannot have a coefficient. To remove the coefficient, divide both sides by the coefficient, which is -5.

\frac{-5x}{-5}=\frac{6}{-5}

Simplify.

x=-\frac{6}{5}

WARRIOR [948]3 years ago
4 0

Question: -2x + 8 = 3x + 14

Steps:

1. Subtract 3x from both sides

-2x - 3x + 8 = 3x - 3x + 14

2. Simplify:

-5x + 8 = 14

3. Then, subtract 8 from both sides:

-5x + 8 - 8 = 14 - 8

4. Simplify,

-5x = 6

5. Then, divide both sides by -5

-5x/-5 = 6/-5

6. Simplify,

x = -6/5 <--------------- Answer


Hope this helped!!!!

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3 years ago
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Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
Suppose 15 quarts of a solution that is 35% antifreeze is mixed with 5 quarts of a solution that is 72% antifreeze. 1.how many q
Finger [1]

Answer:

1. 8.85 quarts

2. 44.25%

Step-by-step explanation:

In 15 quarts of a solution with percentage of antifreeze = 35%

Amount of antifreeze = 35% × 15

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that solution is mixed with 5 quarts of a solution with percentage of antifreeze = 72%

Amount of antifreeze = 72% × 5

                                    = 0.72 × 5

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Total amount of mixture = 15 quarts + 5 quarts = 20 quarts

1. Now we will calculate the total amount of antifreeze in the resulting mixture.

= 5.25 + 3.6 = 8.85 quarts

2. The percentage of the resulting mixture is antifreeze

= \frac{8.85}{20}\times 100

= 44.25%

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3 0
3 years ago
Why is the vertex of vertex form y=a(x-h)^2+k (h,k) rather than (-h,k)? If that was y=2(x-5)^2+6, the vertex would be at (5,6) w
Sindrei [870]

9514 1404 393

Answer:

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Step-by-step explanation:

Vertex form is an instance of the transformation of parent function f(x) = x². It is vertically scaled by a factor of 'a', and translated so the vertex is point (h, k). That is, the transformed vertex is h units right and k units up from that of the parent function (0, 0).

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__

When you compare the form to your specific instance, you need to pay attention to what it is that you're comparing. As the attachment shows, ...

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Hence the vertex is (h, k) = (5, 6). The second attachment shows this on a graph.

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