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Allushta [10]
3 years ago
9

How do you solve this?-2x+8=3x+14thanks

Mathematics
2 answers:
kobusy [5.1K]3 years ago
7 0

Given:

-2x+8=3x+14

Our goal is to isolate x on one side of the variable with no coefficient. Let's begin. First, let's get subtract 3x from both sides to cancel the +3x on the right. We are then left with:

-5x+8=14

Next, subtract 8 from both sides to cancel the +8 on the right. This isolates x on the left side. When we do that, we get:

-5x=6

Since we are solving for x, x cannot have a coefficient. To remove the coefficient, divide both sides by the coefficient, which is -5.

\frac{-5x}{-5}=\frac{6}{-5}

Simplify.

x=-\frac{6}{5}

WARRIOR [948]3 years ago
4 0

Question: -2x + 8 = 3x + 14

Steps:

1. Subtract 3x from both sides

-2x - 3x + 8 = 3x - 3x + 14

2. Simplify:

-5x + 8 = 14

3. Then, subtract 8 from both sides:

-5x + 8 - 8 = 14 - 8

4. Simplify,

-5x = 6

5. Then, divide both sides by -5

-5x/-5 = 6/-5

6. Simplify,

x = -6/5 <--------------- Answer


Hope this helped!!!!

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<em>Comment on the attachment</em>

You see that I did not maintain strict alignment between quotient terms and dividend terms. For polynomial long division, this is less important than for numerical long division.

In numerical long division, the value of a digit is determined by its place relative to the decimal point and other digits. If a digit gets moved a position right or left, its value changes, so it is important to put and keep digits in the appropriate place. Zeros are used as necessary in the quotient to help do this.

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hello

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