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3 years ago

Eq-45 what type of boat requires navigation lights?

Physics

1 answer:

irina [24]3 years ago

8 0

All the boats operating at night requires Navigation light.

Navigation light helps prevent collisions between boats and see if visibility is poor. The types of boat are : Rowboats, Tug boats, Vessels, Sailboat etc.

Various boats have different lightning color to show its use and side of the boat.

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Stars give off a tremendous amount of thermal and ________ energy.(1 point) chemical chemical electrical electrical nuclear nucl

Olegator [25]

I believe the answer is Nuclear energy

8 0

1 year ago

The human ear canal is, on average, 2.5cm long and aids in hearing by acting like a resonant cavity that is closed on one end an

Troyanec [42]

Answer:

$3400$ Hz

Explanation:

We know that

1 cm = 0.01 m

$L$ = Length of the human ear canal = 2.5 cm = 0.025 m

$V$ = Speed of sound = 340 ms⁻¹

$f$ = First resonant frequency

The human ear canal behaves as a closed pipe and for a closed pipe, nth resonant frequency is given as

$f = \frac{(2n - 1)V}{4L}$

for first resonant frequency, we have n = 1

Inserting the values

$f = \frac{(2(1) - 1) 340}{4(0.025)}$

$f = \frac{340}{4(0.025)}$

$f = 3400$ Hz

4 0

3 years ago

What information can scientists obtian from tree rings

Alexandra [31]

What information can scientists obtain from tree rings?

Answer's <u>I chose</u>:

<h3>how narrow the rings are</h3><h3>how the climate changed in the tree’s life</h3><h3>how wide the rings are</h3>

Please <u>correct</u> me if there are <em>more </em>or <em>less</em>

Please give a brainliest and a thanks.

5 0

3 years ago

HELP ME PLEASE WITH MY HOMEWORK ILL GIVE BRAINLIEST

nadezda [96]

Answer: Mass

Explanation:

8 0

2 years ago

At the Indianapolis 500, you can measure the speed of cars just by listening to the difference in pitch of the engine noise betw

allsm [11]

To develop this problem it is necessary to apply the concepts related to the Dopler effect.

The equation is defined by

$f_i = f_0 \frac{c}{c+v}$

Where

$f_h$ = Approaching velocities

$f_i$ = Receding velocities

c = Speed of sound

v = Emitter speed

And

$f_h = f_0 \frac{c}{c+v}$

Therefore using the values given we can find the velocity through,

$\frac{f_h}{f_0}=\frac{c-v}{c+v}$

$v = c(\frac{f_h-f_i}{f_h+f_i})$

Assuming the ratio above, we can use any f_h and f_i with the ratio 2.4 to 1

$v = 353(\frac{2.4-1}{2.4+1})$

$v = 145.35m/s$

Therefore the cars goes to 145.3m/s

7 0

2 years ago