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HACTEHA [7]
1 year ago
14

The area on an entrance ramp where you increase speed to that of expressway traffic is the ______? * 1 point deceleration lane m

edian lane entrance lane acceleration lane
Physics
1 answer:
lions [1.4K]1 year ago
8 0

The area on an entrance ramp where you increase speed to that of expressway traffic is the <u>acceleration lane.</u>

<u></u>

So the correct option is (D) that is acceleration lane.

A section or lane of adjustment for speed that has extra flooring on the borders of the lanes of traffic to let vehicles to accelerate until they merge with the flow of traffic.

Drivers must reach the posted speed limit before entering the acceleration lane, signal, locate a gap in traffic, and then merge.

Drivers can accelerate or decelerate in an area not being used by high-speed through traffic by using acceleration/deceleration lanes, also known as speed-change lanes or auxiliary lanes. The abrupt change in pace can result in stop-and-go traffic, crashes, and other problems on freeways and some major streets. These issues can be reduced by including acceleration/deceleration lanes in the roadway design.

Learn more about acceleration lane:

brainly.com/question/14344386

#SPJ4

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Which of the following statements regarding heuristics and empiricism is true? A. Heuristics allows a priori theoretical concep
WITCHER [35]

Answer: <em>Option (A) is correct.</em>

Explanation:

A heuristic is  often referred to as an approach to solving problems or discovery that subjects a method, which is considered to be practical although might not be guaranteed to be perfect, optimal, or rational, but sufficient for reaching to goal.

Empiricism is known as a theory under which one can states that knowledge can only be imparted from the sensory experience. It is considered to be one of the main notions underlying in epistemology, i.e. known as the study of human knowledge, alongside skepticism and rationalism.

5 0
2 years ago
A moving curling stone, A, collides head on with stationary stone, B. Stone B has a larger mass than stone A. If friction is neg
Kitty [74]

Answer:

The correct answer is option 'c': Smaller stone rebounds while as larger stone remains stationary.

Explanation:

Let the velocity and the mass of the smaller stone be 'm' and 'v' respectively

and the mass of big rock be 'M'

Initial momentum of the system equals

p_i=mv+0=mv

Now let after the collision the small stone move with a velocity v' and the big roch move with a velocity V'

Thus the final momentum of the system is

p_f=mv'+MV'

Equating initial and the final momenta we get

mv=mv'+MV'\\\\m(v-v')=MV'.....i

Now since the surface is frictionless thus the energy is also conserved thus

E_i=\frac{1}{2}mv^2

Similarly the final energy becomes

E_f=\frac{1}{2}mv'^2+\frac{1}{2}MV'^2\

Equating initial and final energies we get

\frac{1}{2}mv^2=\frac{1}{2}mv'^2+\frac{1}{2}MV'^2\\\\mv^2=mv'^2+MV'^2\\\\m(v^2-v'^2)=MV'^2\\\\m(v-v')(v+v')=MV'^2......(ii)

Solving i and ii we get

v+v'=V'

Using this in equation i we get

v'=\frac{v(m-M)}{(M-m)}=-v

Thus putting v = -v' in equation i  we get V' = 0

This implies Smaller stone rebounds while as larger stone remains stationary.

4 0
3 years ago
People who drink coffee are more likely to develop cancer
krok68 [10]

Answer:

The answer is False

8 0
2 years ago
Read 2 more answers
Two bicycle tires are set rolling with the same initial speed of 3.30 m/s along a long, straight road, and the distance each tra
vredina [299]

Answer:

At low pressure- \mu_{k}=0.02315

At high pressure- \mu_{k}=0.00445

Explanation:

Initial speed, V_{i}=3.3 m/s

Final speed, V_{f}=3.3/2= 1.65 m/s

Net horizontal force due to rolling friction F_{net}=\mu_{k} mg where m is mass, g is acceleration due to gravity, \mu_{k} is coefficient of rolling friction

From kinematic relation, V_{f}^{2}- V_{i}^{2}=2ad

For each tire,

V_{f}^{2}- V_{i}^{2}=2\mu_{k}gd

Making \mu_{k} the subject

\mu_{k}=\frac {V_{f}^{2}- V_{i}^{2}}{2gd}

Under low pressure of 40 Psi, d=18 m

\mu_{k}=\frac {1.65^{2}- 3.3^{2}}{2*9.8*18}=-0.02315

Therefore, \mu_{k}=0.02315

At a pressure of 105 Psi, d=93.7

\mu_{k}=\frac {1.65^{2}- 3.3^{2}}{2*9.8*93.7}=-0.00445

Therefore, \mu_{k}=0.00445

4 0
2 years ago
What is the purpose of heat index
Nookie1986 [14]
<span>It tells how hot it really feels when the relative humidity is factored in with the actual air temperature.
hope this helps</span>
7 0
3 years ago
Read 2 more answers
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