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MA_775_DIABLO [31]

3 years ago

9

A pickup truck’s gas tank can hold 19.2 gallons and i can go 460.8 miles on a single tank of gas. How many miles per gallon does

it get?

2 answers:

kipiarov [429]3 years ago

6 0

Divide 460.8 by 19.2 to get 8.375 mpg.

blondinia [14]3 years ago

6 0

First divide 460.8 & 19.2 aka> 4608 & 192

Answer:24 mph

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In a doctor's waiting room, there are 14 seats in a row. Eight people are waiting to be seated. There is someone with a very bad

diamong [38]

Answer: 12,972,960

Step-by-step explanation: There are 14 chairs and 8 people to be seated. But among the 8. three will be seated together:

So 5 people and (3) could be considered as 6 entities:

Since the order matters, we have to use permutation:

¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆ x 3!

2,162,160 x 6 = 12,972,960 ways.

Another way to solve this problem is as follow:

5 + (3) people are considered (for the time being) as 6 entities:

The 1st has a choice among 14 ways

The 2nd has a choice among 13 ways

The 3rd has a choice among 12 ways

The 4th has a choice among 11 ways

The 5th has a choice among 10 ways

The 6th has a choice among 9ways

So far there are 14x13x12x11x10x9 = 2,162,160 ways

But the 3 (that formed one group) could seat among themselves in 3!

or 6 ways:

Total number of permutation = 2,162,160 x 6 = 12,972,960

5 0

3 years ago

A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics e

professor190 [17]

Answer:

$\chi^2 =\frac{15-1}{25} 16 =8.96$

The degrees of freedom are given by:

$df = n-1 = 15-1=14$

The p value for this case would be given by:

$p_v =P(\chi^2$

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

Step-by-step explanation:

Information given

$n=15$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =16$ represent the sample variance

$\sigma^2_0 =25$ represent the value that we want to verify

System of hypothesis

We want to test if the true deviation for this case is lesss than 5minutes, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 25$

Alternative hypothesis: $\sigma^2$

The statistic is given by:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And replacing we got:

$\chi^2 =\frac{15-1}{25} 16 =8.96$

The degrees of freedom are given by:

$df = n-1 = 15-1=14$

The p value for this case would be given by:

$p_v =P(\chi^2$

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

6 0

3 years ago

(-30(-7))-(210(-3))=

Vlad [161]

Answer:

840

Step-by-step explanation:

(−30)(−7) − (210)(−3)

=210 − (210)(−3)

=210 − (−630)

=840

Hope this helps!

brainliest?

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3 0

2 years ago

Read 2 more answers

How many centimeters are in 1 mile

kvasek [131]

Answer:

1 mile = 160934 cm

Step-by-step explanation:

1 mile = 1609.34 m

1 m = 100 cm

1 mile = 1609.34 * 100 = 160934 cm

3 0

3 years ago

Read 2 more answers

A group of pennies made in 2018 are weighed. The mean is approximately 2.5 grams

Hatshy [7]

Answer:

* The mean (a measure of central tendency) weight value is the average of the weights of all pennies in the study.

* The standard deviation (a measure of variability or dispersion) describes the lowest and highest any individual penny weight can be. Subtracting 0.02g from the mean, you get the lowest penny weight in the group.

Step-by-step explanation:

Recall that a penny is a money unit. It is created/produced, just like any other commodity. As a matter of fact, almost all types of money or currency are manufactured; with different materials ranging from paper to solid metals.

A group of pennies made in a certain year are weighed. The variable of interest here is weight of a penny.

The mean weight of all selected pennies is approximately 2.5grams.

The standard deviation of this mean value is 0.02grams.

In this context,

* The mean (a measure of central tendency) weight value is the average of the weights of all pennies in the study.

* The standard deviation (a measure of variability or dispersion) describes the lowest and highest any individual penny weight can be. Subtracting 0.02g from the mean, you get the lowest penny weight in the group.

Likewise, adding 0.02g to the mean, you get the highest penny weight in the group.

Hence, the weight of each penny in this study, falls within

[2.48grams - 2.52grams]

4 0

2 years ago