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3 years ago

If two gases react, pumping more gas into the reaction container will _____ the rate of the reaction.

Chemistry

2 answers:

d1i1m1o1n [39]3 years ago

5 0

Answer:

increase the rate of reaction

zimovet [89]3 years ago

3 0

Answer:

the answer is A it will increase

Explanation:

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Which tool was used to collect the solid product of the chemical reaction? the balance the funnel with the filter paper the Erle

Serggg [28]

Answer:

the funnel with the filter paper

Explanation:

When the mixture of solution is poured through the funnel with filter paper, the liquid solution can pass through the filter paper and gets collected in the beaker (filtrate) while the solid products are too large to pass through the filter paper, so they remain on the funnel (residue).

With this tool, the solid product could be separated from the mixture.

3 0

3 years ago

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Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the following reaction equation. 2H202(aq)

inn [45]

Answer : The temperature for non-catalyzed reaction needed will be 456 K

Explanation :

Activation energy : The energy required to initiate the reaction is known as activation energy.

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

Since, the rate for both the reaction are equal.

$K_1=K_2$

$A\times e^{\frac{-Ea_1}{RT_1}}=A\times e^{\frac{-Ea_2}{RT_2}}$

$\frac{Ea_1}{T_1}=\frac{Ea_2}{T_2}$ ..........(1)

where,

$Ea_1$ = activation energy for non-catalyzed reaction = 75 kJ/mol

$Ea_2$ = activation energy for catalyzed reaction = 49 kJ/mol

$T_1$ = temperature for non-catalyzed reaction = ?

$T_2$ = temperature for catalyzed reaction = $25^oC=273+25=298K$

Now put all the given values in the above formula 1, we get:

$\frac{Ea_1}{T_1}=\frac{Ea_2}{T_2}$

$\frac{75kJ/mol}{T_1}=\frac{49kJ/mol}{298K}$

$T_1=456K$

Therefore, the temperature for non-catalyzed reaction needed will be 456 K

3 0

3 years ago

Aight imma let you guys i

katrin [286]

Answer:

Explanation:

it is right

6 0

3 years ago

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Calculate the number of Calories present in a chocolate chip cookie that contains 19 g carbohydrate, 3 g protein, and 9 g fat.

agasfer [191]

Im unsure :( maybe try looking up a calorie calculator

5 0

3 years ago

Consider a simple reaction in which a reactant AA forms products: A→productsA→products What is the rate law if the reaction is z

levacccp [35]

Answer :

The rate law expression for zero order reaction will be:

$Rate=k[A]^0$

The rate law expression for first order reaction will be:

$Rate=k[A]^1$

The rate law expression for second order reaction will be:

$Rate=k[A]^2$

Zero order reaction : There is no affect on the rate law.

First order reaction : The rate law becomes doubled.

Second order reaction : The rate law becomes quadrupled.

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The given reaction is:

$A\rightarrow Products$

The rate law expression for zero order reaction will be:

$Rate=k[A]^0$

The rate law expression for first order reaction will be:

$Rate=k[A]^1$

The rate law expression for second order reaction will be:

$Rate=k[A]^2$

Now we have to determine that if doubling of the concentration of A then the rate of reaction will be:

As we know that the zero order reaction does not depend on the concentration of reactant. So, there is no affect on the rate law.

As we know that the first order reaction depend on the concentration of reactant. So, the rate law becomes doubled.

As we know that the second order reaction depend on the concentration of reactant. So, the rate law becomes quadrupled.

5 0

4 years ago