Answer:
Solution
Explanation:
Solution is a process in chemical weathering and it is the process of dissolving or removing rock in a solution through the activities of acid rain or solution. Chemical weathering refer to the process where rocks interact with chemical solutions or acid rain which can result in His integration.
The correct answer is D. the star is getting farther away.
When the light has red-shifted, it shows that everything is moving away from a certain point. This is known as the Doppler effect and proves the Big Bang (which would be the center point that everything is moving away from). Just as a 'for your information', blue shift is when the star is moving towards us.
Hope I helped :)
Answer:
8.6 miles
Explanation:
In order to calculate the straight-line distance between the starting point and the ending point, we need to resolve each part of the displacement into two perpendicular directions, let's say horizontal (x) and vertical (y) directions.
In the first part, Erica moves for 5.2 miles 25∘ north of east. Resolving into the two directions:
![d_{1x} = 5.2 cos 25^{\circ}=4.7 mi\\d_{1y} = 5.2 sin 25^{\circ} =2.2 mi](https://tex.z-dn.net/?f=d_%7B1x%7D%20%3D%205.2%20cos%2025%5E%7B%5Ccirc%7D%3D4.7%20mi%5C%5Cd_%7B1y%7D%20%3D%205.2%20sin%2025%5E%7B%5Ccirc%7D%20%3D2.2%20mi)
In the second part, Erica moves 5.0 miles north, so the components are
![d_{2x} = 0\\d_{2y} = 5.0 mi](https://tex.z-dn.net/?f=d_%7B2x%7D%20%3D%200%5C%5Cd_%7B2y%7D%20%3D%205.0%20mi)
So the components of the net displacement are
![d_x = d_{1x}+d_{2x}=4.7+0 = 4.7 mi\\d_y = d_{1y}+d_{2y} =2.2+5.0 = 7.2 mi](https://tex.z-dn.net/?f=d_x%20%3D%20d_%7B1x%7D%2Bd_%7B2x%7D%3D4.7%2B0%20%3D%204.7%20mi%5C%5Cd_y%20%3D%20d_%7B1y%7D%2Bd_%7B2y%7D%20%3D2.2%2B5.0%20%3D%207.2%20mi)
And the magnitude of the net displacement is
![d=\sqrt{d_x^2 +d_y^2}=\sqrt{4.7^2+7.2^2}=8.6 mi](https://tex.z-dn.net/?f=d%3D%5Csqrt%7Bd_x%5E2%20%2Bd_y%5E2%7D%3D%5Csqrt%7B4.7%5E2%2B7.2%5E2%7D%3D8.6%20mi)
Answer:
![a_2\ =\ -33.65\ m/s^2](https://tex.z-dn.net/?f=a_2%5C%20%3D%5C%20-33.65%5C%20m%2Fs%5E2)
Explanation:
Given,
For the first rocket,
- Initial velocity of the first rocket A =
![u_1\ =\ 4600\ m/s.](https://tex.z-dn.net/?f=u_1%5C%20%3D%5C%204600%5C%20m%2Fs.)
- Acceleration of the first rocket =
![a_1\ =\ -18\ m/s^2](https://tex.z-dn.net/?f=a_1%5C%20%3D%5C%20-18%5C%20m%2Fs%5E2)
For the second rocket,
- Initial velocity of the second rocket B =
![u_2\ =\ 8200 m/s.](https://tex.z-dn.net/?f=u_2%5C%20%3D%5C%208200%20m%2Fs.)
- Displacement of both the rockets A and B = s = 0 m
Fro the first rocket,
Let 't' be the time taken by the first rocket A for whole the displacement
![\therefore s\ =\ u_1t\ +\ \dfrac{1}{2}a_1t^2\\\Rightarrow 0\ =\ 4600t\ -\ 0.5\times 18t^2\\\Rightarrow t\ =\ \dfrac{4600}{0.5\times 18}\\\Rightarrow t\ =\ 511.11 sec](https://tex.z-dn.net/?f=%5Ctherefore%20s%5C%20%3D%5C%20u_1t%5C%20%2B%5C%20%5Cdfrac%7B1%7D%7B2%7Da_1t%5E2%5C%5C%5CRightarrow%200%5C%20%3D%5C%204600t%5C%20-%5C%200.5%5Ctimes%2018t%5E2%5C%5C%5CRightarrow%20t%5C%20%3D%5C%20%5Cdfrac%7B4600%7D%7B0.5%5Ctimes%2018%7D%5C%5C%5CRightarrow%20t%5C%20%3D%5C%20511.11%20sec)
Let
be the acceleration of the second rocket B for the same time interval
from the kinematics,
![\therefore s\ =\ ut\ +\ \dfrac{1}{2}at^2\\\Rightarrow s\ =\ u_2t\ +\ \dfrac{1}{2}a_2t^2\\\Rightarrow a_2\ =\ \dfrac{2s\ -\ 2u_2t}{t^2}\\\Rightarrow a_2\ =\ \dfrac{0\ -\ 2u_2t}{t^2}\\](https://tex.z-dn.net/?f=%5Ctherefore%20s%5C%20%3D%5C%20ut%5C%20%2B%5C%20%5Cdfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5CRightarrow%20s%5C%20%3D%5C%20u_2t%5C%20%2B%5C%20%5Cdfrac%7B1%7D%7B2%7Da_2t%5E2%5C%5C%5CRightarrow%20a_2%5C%20%3D%5C%20%5Cdfrac%7B2s%5C%20-%5C%202u_2t%7D%7Bt%5E2%7D%5C%5C%5CRightarrow%20a_2%5C%20%3D%5C%20%5Cdfrac%7B0%5C%20-%5C%202u_2t%7D%7Bt%5E2%7D%5C%5C)
![\Rightarrow a_2\ =\ -\dfrac{2u_2}{t}\\\Rightarrow a_2\ =\ -\dfrac{2\times 8600}{511.11}\\\Rightarrow a_2\ =\ -33.65\ m/s^2](https://tex.z-dn.net/?f=%5CRightarrow%20a_2%5C%20%3D%5C%20-%5Cdfrac%7B2u_2%7D%7Bt%7D%5C%5C%5CRightarrow%20a_2%5C%20%3D%5C%20-%5Cdfrac%7B2%5Ctimes%208600%7D%7B511.11%7D%5C%5C%5CRightarrow%20a_2%5C%20%3D%5C%20-33.65%5C%20m%2Fs%5E2)
Hence the acceleration of the second rocket B is -33.65\ m/s^2.
Answer:
The Corona.
Explanation:
The Corona is the outermost part of the Sun. Usually, it is nto visible due to the light emitted by the Sun. During a total solar eclipse, that is the moon comes between the Earth and the Sun, the glowing white edge around the eclipse is the Corona.