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tensa zangetsu [6.8K]
4 years ago
8

Mr. Garcia uses magnets to hold a poster on a steel filing cabinet because a main component of steel is _____.

Physics
2 answers:
KonstantinChe [14]4 years ago
8 0
The main component of steel is iron ... the mother of all magnetic material.
kirill [66]4 years ago
4 0

Answer:

Iron

Explanation:

Steel is the purest form of iron with a little amount of carbon mixed in it. As we all know that iron is attracted towards magnet therefore we can say that steel can also be attracted towards magnet.

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Who is known as the father of India​
balandron [24]

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the answer is

Mahatma Gandhi

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Two trains collide in a messy train
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b

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Se dispone de dos vasos con agua a 20 grados y queremos calentarlo hasta alcanzar 50 grados. Si el primero contiene 0,5l y el se
BigorU [14]

Answer:

The cup with 0.5L

Explanation:

To know what amount of water you take into account the specific heat of the water. The specific heat of water is:

c_{water}=4186\frac{J}{kg\°C}

Thus, 4186 J of energy are needed to icrease the temperature of 1 kg water in 1°C. Then, more grams of water will need more energy.

You have that one cup has 0.5 L and the other one has 750mL = 0.75L

The second cup of water will need more heat because the amount of water contained in the second cup is greater than in the first cup with 0.5L

4 0
3 years ago
Please answer this question.
Len [333]

Answer:

Explanation:

need more work

6 0
3 years ago
A 6.0-kg object moving at 5.0 m/s collides with and sticks to a 2.0-kg object. After the collision the composite object is movin
gogolik [260]

Answer:

a) 23 m/s

Explanation:

  • Assuming no external forces acting during the collision, total momentum must be conserved, as follows:

       p_{o} = p_{f}  (1)

  • The initial momentum p₀, can be written as follows:

       p_{o} =  m_{1}  * v_{1o} + m_{2}* v_{2o} =   6.0 kg * 5.0 m/s + 2.0 kg * v_{2o}  (2)

  • The final momentum pf, can be written as follows:

        p_{f} = (m_{1} + m_{2} )* v_{f}  = 8.0 kg* (-2.0 m/s)  (3)

  • Since (2) and (3) are equal each other, we can solve for the only unknown that remains, v₂₀, as follows:

       v_{2o} = \frac{-6.0kg* 5m/s -8.0 kg*2.0m/s}{2.0kg}  = \frac{-46kg*m/s}{2.0kg} = -23.0 m/s  (4)

  • This means that the 2.0-kg object was moving at 23 m/s in a direction opposite to the 6.0-kg object, so its initial speed, before the collision, was 23.0 m/s.
6 0
3 years ago
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