CAN SOMEONE PLS HELP ME ILL GIVE YOU BRAINLIEST!!!!
2 answers:
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Answer:
7.1 m
Explanation:
Given:
Distance traveled by the student in the first attempt =
Distance traveled by the student in the second attempt =
So, the maximum distance that the student could travel in this attempt =
So, the maximum distance that the student could travel in this attempt =
Since the student first moves straight in a particular direction, rests for a while and then moves some distance in the same direction.
So, the largest distance that the student could possibly be from the starting point would be the largest distance of the final position of the student from the starting point.
And this distance is equal to the sum of the maximum distance possible in the first attempt and the second attempt of walking which is 7.1 m.
Hence, the largest distance that the student could possibly be from the starting point is 7.1 m.
The velocity of the red ball after the collision is 5.8 m/s
Explanation:
In absence of external forces on the system, we can apply the principle of conservation of momentum. The total momentum of the system must be conserved before and after the collision, so we can write:
where:
is the mass of the pool ball
is the initial velocity of the pool ball
is the final velocity of the pool ball
is the mass of the red ball
is the initial velocity of the red ball
is the final velocity of the red ball
Solving the equation for v2, we find the final velocity of the red ball after the collision:
Learn more about collisions:
brainly.com/question/13966693#
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