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Tcecarenko [31]
3 years ago
10

What is the shape of our Milky Way galaxy?

Physics
2 answers:
stepan [7]3 years ago
6 0
Spiral

Hope this helps! c;
sergij07 [2.7K]3 years ago
5 0
D. Hope I helped (::
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Two masses are connected by a string which passes over a pulley with negligible mass and friction. One mass hangs vertically and
lora16 [44]
The tension in the string and the acceleration must be equal for both masses. (See the free body diagrams)





8 0
3 years ago
Weight is measured in units called
Aleksandr-060686 [28]
Pounds

If you are talking about the unit of measurement for weight is that of force it would be Newtons.
8 0
3 years ago
A research-level Van de Graaff generator has a 2.15 m diameter metal sphere with a charge of 5.05 mC on it. What is the potentia
Llana [10]

Answer:

42.3 MV

Explanation:

d = diameter of the metal sphere = 2.15 m

r = radius of the metal sphere

diameter of the metal sphere is given as

d = 2r

2.15 = 2 r

r = 1.075 m

Q = charge on sphere = 5.05 mC = 5.05 x 10⁻³ C

Potential near the surface is given as

V = \frac{kQ}{r}

V = \frac{(9\times 10^{9})(5.05\times 10^{-3})}{1.075}

V = 4.23 x 10⁷ volts

V = 42.3 MV

5 0
4 years ago
Which units would not be appropriate for describing a rotational acceleration?
Y_Kistochka [10]
Ounces would be an inappropriate unit for describing rotational acceleration
6 0
3 years ago
If you want to double the kinetic energy of a gas molecule, by what factor must you increase its momentum?A) 16B) 2^(1/2)
worty [1.4K]

Answer: \sqrt{2}

The linear momentum p is given by the following equation:

p=m.v   (1)

Where m is the mass and v the velocity.

On the other hand, the kinetic energy K is given by:

K=\frac{p^{2}}{2m}   (2)

Which is the same as:

K=\frac{1}{2}m.v^{2}

Now, if we double the kinetic energy, equation (2) changes to:

2K=2\frac{p^{2}}{2m}  

2K=\frac{p^{2}}{m}   (3)

So, if we want to obtain the kinetic energy as shown in (3), the only option that works is increasing momentum by a factor of \sqrt{2} or 2^{1/2}:

Applying this in (2):

K=\frac{(\sqrt{2}p)^{2}}{2m}

K=\frac{(2p)^{2}}{2m}

K=\frac{p^{2}}{m}>>>As we can see, this equation is the same as equation (3)

Therefore, the correct answer is B

3 0
3 years ago
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