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3 years ago

Which statement about DDT best shows how science has been impacted by society?

Physics

1 answer:

pentagon [3]3 years ago

6 0

D.DDT was used in WWII to control malaria and typhus.<span>
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Ferromagnetic materials-

QveST [7]

Answer:

materials which exhibit a spontaneous net magnetization at the atomic level, even in the absence of an external magnetic field.

Explanation:

When a material is placed within a magnetic field, the magnetic forces of the material's electrons will be affected. This effect is known as Faraday's Law of Magnetic Induction. However, materials can react quite differently to the presence of an external magnetic field. This reaction is dependent on a number of factors, such as the atomic and molecular structure of the material, and the net magnetic field associated with the atoms. The magnetic moments associated with atoms have three origins. These are the electron motion, the change in motion caused by an external magnetic field, and the spin of the electrons.

5 0

3 years ago

If magnet A can pick up 3 steel paper clips and magnet B can pick up 11 gold paper clips and which one is stronger?

Nutka1998 [239]

The answer to your question is b

8 0

3 years ago

find the speed of a rolling ball that travels a distance of 10 m over the top of a smooth table in 2.0 seconds

umka21 [38]

The speed is between 5-15

4 0

3 years ago

Read 2 more answers

A series RCL circuit is at resonance and contains a variable resistor that is set to 206Ω. The power dissipated in the circuit i

mash [69]

Answer:

Power dissipated in resistor 532 ohm is 0.503 watt

Explanation:

We have given in first case resistance $R_1=206ohm$

Power dissipated in this resistance is $P_1=1.30watt$

Power dissipated in the resistor is equal to $P=\frac{v_{rms}}^2{R}$

We have to find the power dissipated in the resistor is 1.30 watt

From the relation we can say that $\frac{P_1}{P_2}=\frac{R_2}{R_1}$

$\frac{1.3}{P_2}=\frac{532}{206}$

$P_2=0.503watt$

So power dissipated in resistor 532 ohm is 0.503 watt

5 0

3 years ago

What is the force of impact of a 100 kg diver who falls into a swimming pool and hits the surface of the water and comes to a st

Simora [160]

Answer:

F = 53153.36[N]

Explanation:

In order to solve this problem, we must first use the principle of conservation of energy which is transformed from potential energy to kinetic, in this way we can determine the velocity at which the person enters the water.

$E_{pot}=E_{kin}\\m*g*h=\frac{1}{2}*m*v^{2}$

where:

m = mass = 100 [kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 9 [m]

v = velocity [m/s]

Now replacing we can determinate the velocity.

$v^{2}=2*g*h\\v=\sqrt{2*g*h}\\v=\sqrt{2*9.81*9}\\v = 13.28[m/s]$

Then we can calculate the momentum which can be calculated as the product of force by time, this momentum is also equal to the product of mass by velocity.

$P=m*v\\and\\P =F*t\\F*t=m*v$

Now replacing:

F = impact force [N]

t = time = 0.025 [s]

m = 100 [kg]

v = velocity = 13.28 [m/s]

$F*0.025=100*13.28\\F=53153.36[N]$

8 0

3 years ago