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grin007 [14]
3 years ago
8

An apple farm claims that the average weight of all their apples is 8oz. A sample of 20 apples were picked that had a mean of 7.

77oz and standard deviation of 0.95oz. We want to test whether the mean apple weight is different from 8oz. Assume that the apple weights are normally distributed.
Mathematics
1 answer:
Nimfa-mama [501]3 years ago
5 0

Answer:

The mean apple weight is different from 8oz

Step-by-step explanation:

Claim : An apple farm claims that the average weight of all their apples is 8oz.

H_0:\mu \neq 8\\H_a:\mu = 8

n = 20

Standard deviation =s = 0.95

Since n < 30

So we will use t-test

x = 7.77

t =\frac{x-\mu}{\frac{s}{\sqrt{n}}}

Substitute the values :

t =\frac{7.77-8}{\frac{0.95}{\sqrt{20}}}

t =−1.0827

Since we are not given the significance level

So, we will take 5%

So,α = 0.05

Degree of freedom = df = n-1 = 20-1 = 19

So, using t table

t_{\frac{\alpha}{2} , df}=2.093

Since t critical > t statistic

So, we accept the null hypothesis.

So, The mean apple weight is different from 8oz

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(x-2)(x-1-\sqrt2)=x^2-2x-(1+\sqrt2)x+2(1+\sqrt2)=x^2-(3+\sqrt2)x+2+2\sqrt2

which would be the correct answer, but clearly this option is not listed. Which is silly, because none of the offered solutions are *the* polynomial of lowest degree and leading coefficient 1.

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Answer:

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