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Irina18 [472]
4 years ago
12

The y-component of velocity for a certain 2-D flow field is given as u = 3xy + x2 . Determine the x-component of velocity if the

flow is incompressible.
Engineering
1 answer:
Maslowich4 years ago
8 0

Answer:

-\frac{3x^{2}}{2}

Explanation:

It is given that y component is

v = 3xy + x^{2}

\Rightarrow \frac{\partial v}{\partial y}= 3 x

For an incompressible flow, the continuity equation is written in differential form as

\frac{\partial u}{\partial x}+\frac{\partial v}{\partial y}=0

\Rightarrow \frac{\partial u}{\partial x}= -\frac{\partial v}{\partial y}

\Rightarrow \frac{\partial u}{\partial x}= - 3x

Now solving for x component of velocity is

u = - \int 3x.dx

  = - \frac{3x^{2}}{2}

Therefore, x component of velocity is - \frac{3x^{2}}{2}  

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Answer:

THE CODE FOR THE PROGRAM IS GIVEN BELOW:

#include <iostream>

#include "ConvertTimeHeader.h"

using namespace std;

int main()

{

convertTime convert;

int hr, mn, sc = 0;

 

cout << "Please input hours in 12 hr notation: ";

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return 0;  

 

}

#include <iostream>

#include "ConvertTimeHeader.h"

using namespace std;

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{

try{

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  {hour = hour + 12;

  return hour;}

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  cin.clear();

  cin.ignore();

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  invalidHr(hour);

  throw 10;

 }

   

}

catch (int c) { cout << "Invalid hour input!";}

}

int convertTime::invalidMin (int min)

{

try{

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  {return min;}

 else{

 

  cin.clear();

  cin.ignore();

  cout << "Invalid input! Please input minutes again in correct 12 hour format: ";

  cin >> min;

  invalidMin(min);

  throw 20;

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 }

   

}

catch (int e) { cout << "Invalid minute input!" << endl;}

}

int convertTime::invalidSec(int sec)

{

try{

 if (sec < 60 && sec > 0)

  {return sec;}

 else{

 

  cin.clear();

  cin.ignore();

  cout << "Invalid input! Please input seconds again in correct 12 hour format: ";

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  invalidSec(sec);

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}

catch (int t) { cout << "Invalid second input!" << endl;}

}

void convertTime::printMilTime()

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cout << "Your time converted: " << hour << ":" << min << ":" << sec;

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Explanation:

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