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2 years ago

Calculate the average time it took the car to travel 0.25 What is the average time it took the car to travel 0.25

Chemistry

2 answers:

DedPeter [7]2 years ago

8 1

Answer:

Explanation:

idk why all u guys like trump who do.. hes just a big pain in the a*s.

blaze the wolf

2 years ago

shut the f*ck up this is for work not your bullsh*t

blaze the wolf

2 years ago

biden is a f*cking dumb b*tch im only a child and i can run a country better than his old slow 2 mph walking a*s

yawa3891 [41]2 years ago

4 0

Answer:

2.23 3.13

Explanation:

just did it

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The energy of a photon needed to cause ejection of an electron from a photoemissive metal is expressed as the sum of the binding

slega [8]

Answer:

$Binding\ energy=43.43\times 10^{-20}\ J$

Explanation:

Using the expression for the photoelectric effect as:

$E=h\nu_0+\frac {1}{2}\times m\times v^2$

Also, $E=\frac {h\times c}{\lambda}$

$\nu_0=\frac {c}{\lambda_0}$

Applying the equation as:

$\frac {h\times c}{\lambda}=\frac {hc}{\lambda_0}+\frac {1}{2}\times m\times v^2$

Where,

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

c is the speed of light having value $3\times 10^8\ m/s$

$\lambda$ is the wavelength of the light being bombarded

Given, $\lambda=4.00\times 10^{-7}\ m$

$\frac {hc}{\lambda_0}$ is the binding energy or threshold energy

$\frac {1}{2}\times m\times v^2$ is the kinetic energy of the electron emitted. = $6.26\times 10^{-20}\ J$

Thus, applying values as:

$\frac{h\times c}{\lambda}=Binding\ Energy+Kinetic\ Energy$

$\frac{6.626\times 10^{-34}\times 3\times 10^8}{4.00\times 10^{-7}}\ J=Binding\ Energy+6.26\times 10^{-20}\ J$

$\frac{19.878}{10^{19}\times \:4}\ J=Binding\ Energy+6.26\times 10^{-20}\ J$

$49.69\times 10^{-20}\ J=Binding\ Energy+6.26\times 10^{-20}\ J$

$Binding\ energy=43.43\times 10^{-20}\ J$

5 0

3 years ago

Which is not an indicator for a chemical change?

Anastasy [175]

Answer:

Explanation:

Because it does not change entirely.

8 0

2 years ago

What is erosion? what are the four agents of erosion

Savatey [412]

Answer:

Erosion is the transportation of sediment at the Earth's surface. 4 agents move sediment: Water, Wind, Glaciers, and Mass Wasting (gravity).

Explanation:

3 0

2 years ago

chemist adds of a M iron(III) bromide solution to a reaction flask. Calculate the mass in grams of iron(III) bromide the chemist

Sav [38]

The question is incomplete, here is the complete question:

A chemist adds 370.0 mL of a 2.25 M iron(III) bromide solution to a reaction flask. Calculate the mass in grams of iron(III) bromide the chemist has added to the flask. Round your answer to 3 significant digits

<u>Answer:</u> The mass of iron (III) bromide is 246. grams

<u>Explanation:</u>

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 2.25 M

Molar mass of iron (III) bromide = 295.6 g/mol

Volume of solution = 370.0 mL

Putting values in above equation, we get:

$2.25M=\frac{\text{Mass of solute}\times 1000}{295.6\times 370.0}\\\\\text{Mass of solute}=\frac{2.25\times 295.6\times 370.0}{1000}=246.1g$

Hence, the mass of iron (III) bromide is 246. grams

4 0

2 years ago

Consider the following neutral electron configurations in which n has a constant value. Which configuration would belong to the

Feliz [49]

Answer:

"c" is the element with the most negative electron affinity.

Explanation:

We can obtain the following information from the electron configuration:

Period: Is the level in which the differential electron is in.

Group: Is the sum of all electrons in the last level.

Knowing their ubication in the periodic table, we can classify them as metals, nonmetals or noble gases.

a. 5s² P: 5 G: IIA (2) Metal

b. 5s²5p² P: 5 G: 2 + 2 = IVA (14) Nonmetal

c. 5s²5p⁵ P: 5 G: 2 + 5 = VIIA (17) Nonmetal

d. 5s²5p⁶ P: 5 G: 2 + 6 = VIIIA (18) Noble gas

Noble metals have a low tendency to gain electrons so their electron affinity is neglectable. For elements in the same period, the electron affinity gets more negative from left to right. Therefore, "c" is the element with the most negative electron affinity.

3 0

2 years ago