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3 years ago

Gas is trapped within a container held at a constant temperature. If the volume of the

Chemistry

1 answer:

Citrus2011 [14]3 years ago

6 0

The gas would diffuse as much as it could

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When was helium discoved?

andrey2020 [161]

It was discovered in 1868.i hope this helps you .

4 0

4 years ago

The graph shows the amount of a gaseous product formed over time during two trials of a reaction. A different concentration of a

makkiz [27]

Trial 1 has a lower concentration of the reactant because the because the average rate of the reaction is lower.

<h3>What is a reaction?</h3>

The term reaction has to do with the combination of reactants in order to yield products. Now we know that the reaction profile is used to show the interaction that exists between the reactants and the products.

The y-axis of the graph is for the amount while the x axis of the graph is the reaction time. The rate of reaction is the time taken for a given amount of products to appear or for a given amount of reactants to disappear.

Thus, from the graph, we can see that trial 1 has a lower concentration of the reactant because the because the average rate of the reaction is lower.

Learn more about rate of reaction:brainly.com/question/24266729

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5 0

2 years ago

The degree of polarity of a covalent bond between two atoms is determined by calculating the difference in their

Y_Kistochka [10]

Answer:

C) electronegativities

Explanation:

there is an electronegativity chart that will tell you the charge, then you can subtract between the two and use cut offs for the values to see if you have an ionic, polar covalent, or non polar covalent bond

3 0

3 years ago

Read 2 more answers

1. Cl2 and Brą have approximately the same shape and neither is polar.

dlinn [17]

It is B because it is

3 0

3 years ago

Compute the equilibrium constant for the spontaneous reaction between

Reptile [31]

Answer:

9.8 × 10^21

Explanation:

Equation of the reaction;

Cd(s) + Ni^2+(aq) ----> Cd^2+(aq) + Ni(s)

E°cell= E°cathode - E°anode

E°cathode= -0.25 V

E°anode = -0.40 V

E°cell= -0.25 - (-0.40)

E°cell = 0.65 V

∆G= -nFE°cell

∆G= -(2 × 96500 × 0.65)

∆G = -125450 J

From;

∆G= -RTlnK

lnK = ∆G/-RT

K= e^∆G/-RT

K= e^-[-(125450/8.314 × 298)]

K= 9.78 × 10^21

5 0

4 years ago