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iragen [17]
3 years ago
15

In the reaction C + O2 → CO2, 18 g of carbon react with oxygen to produce 72 g of carbon dioxide. What mass of oxygen would be n

eeded in the reaction?
18 g
54 g
72 g
90 g
Chemistry
2 answers:
kompoz [17]3 years ago
5 0

Answer:

54g

Explanation:

melamori03 [73]3 years ago
3 0

Answer:

54 g

Explanation:

Given data:

Mass of carbon = 18 g

Mass of CO₂ = 72 g

Mass of oxygen needed = ?

Solution:

Chemical reaction:

C + O₂     →       CO₂

according to law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by French chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

In given photosynthesis reaction:

6CO₂ + 6H₂O + energy → C₆H₁₂O₆ + 6O₂

there are six carbon atoms, eighteen oxygen atoms and twelve hydrogen atoms on the both side of equation so this reaction followed the law of conservation of mass.

In a similar way,

C   +    O₂     →       CO₂

18 g +   X      = 72

X = 72 -18

X = 54 g

Thus, 54 g of O₂ are required.

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A sample of milk kept at 25 °C is found to sour 40 times as rapidly as when it is kept at 4 °C. Estimate the activation energy f
irga5000 [103]

Answer:

120.575 kJ is the activation energy for the souring process.

Explanation:

The formula for an activation energy is given as:

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant at 25^oC = 40k

K_2 = rate constant at 4^oC = k

Ea = activation energy for the reaction = ?

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 25^oC=273+25=298 K

T_2 = final temperature = 4^oC=273+4=277 K

Now put all the given values in this formula, we get:l

\log (\frac{k}{40k})=\frac{Ea}{2.303\times 8.314 J/mol K}[\frac{1}{298K}-\frac{1}{277 K}]

E_a=120,575.61J=120.575 kJ

120.575 kJ is the activation energy for the souring process.

7 0
3 years ago
Find ΔHrxn for the following reaction: <br><br> 2PbS(s)+3O2(g)→2PbO(s)+2SO2(g)
ch4aika [34]

Answer:

ΔH°rxn = -827.5 kJ

Explanation:

Let's consider the following balanced equation.

2 PbS(s) + 3 O₂(g) → 2 PbO(s) + 2 SO₂(g)

We can calculate the standard enthalpy of reaction (ΔH°rxn) from the standard enthalpies of formation (ΔH°f) using the following expression.

ΔH°rxn = [2 mol × ΔH°f(PbO(s)) + 2 mol × ΔH°f(SO₂(g) )] - [2 mol × ΔH°f(PbS(s)) + 3 mol × ΔH°f(O₂(g) )]

ΔH°rxn = [2 mol × ΔH°f(PbO(s)) + 2 mol × ΔH°f(SO₂(g) )] - [2 mol × ΔH°f(PbS(s)) + 3 mol × ΔH°f(O₂(g) )]

ΔH°rxn = [2 mol × (-217.32 kJ/mol) + 2 mol × (-296.83)] - [2 mol × (-100.4) + 3 mol × 0 kJ/mol]

ΔH°rxn = -827.5 kJ

5 0
3 years ago
The highest energy occupied molecular orbital in the C-C bond of the C2 molecule is?
Butoxors [25]

The highest energy occupied molecular orbital in the C-C bond of the C₂ molecule is 2pπ orbitals.

<h3>What is Molecular Orbital Theory?</h3>

According to this theory,

  • Molecular orbitals are formed by intermixing of atomic orbitals of two or more atoms having comparable energies
  • The number of molecular orbitals formed is equal to the number of atomic orbitals combined.
  • The shape of molecular orbitals formed depends on the type of atomic orbitals combined
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  • Bonding M.O. is formed by the additive effect of atomic orbitals and thus, has lower energy and high stability.
  • Antibonding M.O. is formed by the subtractive effect of atomic orbitals and thus, has higher energy and low stability.
  • Bonding M.O. is represented by \sigma, \pi, \delta while Antibonding M.O. is represented by \sigma^*, \pi^*, \delta^*\\

Molecular Orbital Diagram of C₂

Learn more about Molecular Orbital Theory:

brainly.com/question/17371976

#SPJ4

5 0
1 year ago
Which natural law do biogeochemical cycles address?
emmainna [20.7K]
Im not completely sure but It might be Cycling of Matter
4 0
3 years ago
Read 2 more answers
Out of magnesium and Calcium which element is more reactive give reason​
SIZIF [17.4K]

Answer:

Calcium is more reactive.

Explanation:

It is higher in the reactivity series, and contains more energy levels.

5 0
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