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3 years ago

How many mL of a 0.300 M AgNO3 solution will it take to make 500 mL of a 0.100 M AgNO3 solution?

Chemistry

2 answers:

Anarel [89]3 years ago

8 0

EXAMPLE: What is the molarity of a solution made by dissolving 5.67 g of potassium chloride in enough water to make 100.0 mL of solution? This data gives a relationship between amount of solute and volume of solution: 5.67 g KCl / 100.0 mL. To find molarity we must convert grams KCl to moles KCl and mL solution to L: 5.67 g KCl 1 mol KCl 1000 mL 0.760 mol KCl x x = or 0.760 M KCl 100.0 mL 74.6 g KCl L L

Nikolay [14]3 years ago

4 0

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A team of engineers is doing a cost-benefit analysis to determine whether

beks73 [17]

Answer:

1) The risk of high cost due to increased resource requirements

2) The risk of late entry into the (a changed) market

Explanation:

The analysis being performed by the engineers = A cost benefit analysis to determine if a new technology should be developed

A cost-benefit analysis is a process of appraising or measuring the advantages, benefits of a policy, action or decision, so as to find the (equilibrium) balance point between the costs of the decision or action

The risk to be considered are;

1) The risk of high cost due to increased resource requirements

The increased cost required for the development of the new technology now which due to the unlikely existence of a similar invention in the market that will give them an advantage of increased profits

2) The risk of late entry into the (a changed) market

The changes in the consumer preferences, market landscape, and the likely introduction into the market of a similar invention by the competition in the near future which will reduce the amount of profits that can be gained from the invention

3 0

3 years ago

PLEASE SOMEONE HELP ME WITH THIIS QUESTION

sdas [7]

Answer:

The correct answer is - 5 carbon compounds due to low to high intermolecular forces between their molecules.

Explanation:

Bottle C has gas in it and we know that alkane has carbon and hydrogen only which means they have a single sigma bond between them and very low intermolecular forces in between molecules and are present mostly at gaseous state. Thus, bottle C has alkane.

Alcohols have -OH group that can form rarely two pi bonds which means they have intermediate intermolecular force whereas acids have -cooH group with a high molecular force so bottle B with liquid is alcohol and A has acid.

3 0

3 years ago

2-phosphoglycerate(2PG) is converted to phosphoenolpyruvate (PEP) by the enzyme enolase. The standard free energy change(deltaGo

pogonyaev

Answer:

The correct option is: (D) -2.4 kJ/mol

Explanation:

Chemical reaction involved: 2PG ↔ PEP

Given: The standard Gibb's free energy change: ΔG° = +1.7 kJ/mol

Temperature: T = 37° C = 37 + 273.15 = 310.15 K (∵ 0°C = 273.15K)

Gas constant: R = 8.314 J/(K·mol) = 8.314 × 10⁻³ kJ/(K·mol) (∵ 1 kJ = 1000 J)

Reactant concentration: 2PG = 0.5 mM

Product concentration: PEP = 0.1 mM

Reaction quotient: $Q_{r} =\frac{\left [ PEP \right ]}{\left [ 2PG \right ]} = \frac{0.1 mM}{0.5 mM} = 0.2$

To find out the Gibb's free energy change at 37° C (310.15 K), we use the equation:

$\Delta G = \Delta G^{\circ } + 2.303 R T log Q_{r}$

$\Delta G = 1.7 kJ/mol + [2.303 \times (8.314 \times 10^{-3} kJ/(K.mol))\times (310.15 K)] log (0.2)$

$\Delta G = 1.7 + [5.938] \times (-0.699) = 1.7 - 4.15 = (-2.45 kJ/mol)$

Therefore, the Gibb's free energy change at 37° C (310.15 K): ΔG = (-2.45 kJ/mol)

4 0

3 years ago

Why ozone is important to organic chemistry

Nikolay [14]

Answer:

Ozone is good in the stratosphere because it absorbs all of the most energetic ultraviolet radiation (UV-C), most of the UV-B radiation and some of the least energetic UV radiation (UV-A). Ozone is “bad” in the troposphere because it is harmful to breathe and is the primary component of smog in summer.

5 0

3 years ago

What mass of CO was used up in the reaction with an excess of oxygen gas if 24.7g of carbon dioxide is formed? 2 CO + O2 > 2

Zolol [24]

Balance Chemical Equation,
2 CO + O₂ → 2CO₂
Acc. to this reaction,
88 g (2 mole) of CO₂ was produced when = 56 g (2 mole)of CO was reacted
So,
24.7 g of CO₂ will be produced by reacting = X g of CO

Solving for X,
X = (56 g × 24.7 g) ÷ 88 g

X = 2.26 g ÷ 88 g

X = 0.0257 g of CO

Result:
0.0257 g of CO is required to be reacted with excess of O₂ to produce 24.7 g of CO₂.

7 0

2 years ago