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3 years ago

HELP MEEEE!!!!!!!!!!!

Chemistry

1 answer:

Mekhanik [1.2K]3 years ago

7 0

Answer:

The answer is A

Explanation:

That is the only answer that even remotely resembles an ultrasound hope this answered your question.

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A total of 25.0 mL of 0.150 M potassium hydroxide (KOH) was required to neutralize 15.0 mL of sulfuric acid (H2SO4) of unknown c

Kamila [148]

We are told that KOH is being used to completely neutral H₂SO₄ according to the following reaction:

KOH + H₂SO₄ → H₂O + KHSO₄

If KOH can completely neutralize H₂SO₄, then there must be an equal amount of moles of each as they are in a 1:1 ratio:

0.025 L x 0.150 mol/L = .00375 mol KOH

0.00375 mol KOH x 1 mole H₂SO₄/1 mole KOH = 0.00375 mol H₂SO₄

We are told we have 15 mL of H₂SO₄ initially, so now we can find the original concentration:

0.00375 mol / 0.015 L = 0.25 mol/L

The concentration of H₂SO₄ being neutralized is 0.25 M.

6 0

3 years ago

Can someone explain how to do this, I don't understand?

solniwko [45]

Answer:

a) 2

b) 3

c) 5

d) 6

Explanation:

7 0

2 years ago

What is the necessary voltage to power the electrolysis of molten sodium chloride?

sammy [17]

4V is the necessary voltage to power the electrolysis of molten sodium chloride.

To create sodium metal and chlorine gas, molten (liquid) sodium chloride can be electrolyzed. A Down's cell is the name of the electrolytic cell utilised in the procedure. The liquid sodium ions in a Down's cell are converted to liquid sodium metal at the cathode. Liquid chlorine ions are oxidised to chlorine gas at the anode. Below is an illustration of the reactions and cell potentials:

oxidation: $2Cl^{-} (l)$ → $Cl_{2} (g)$ + $2e^{-}$ E°= -1.36V

reduction: $Na^{+} (l) + e^{-}$ → $Na (l)$ E°= -2.71V

overall : $2Na^{+} (l) + 2Cl^{-} (l)$ → $2Na(l) +Cl_{2} (g)$ E° $_{cell}$ = -4.07V

For this electrolysis to take place, the battery needs to supply more than 4 volts. The only means to obtain pure sodium metal is by this reaction, which also serves as a significant source of chlorine gas generation. Swimming pools and other surfaces are frequently cleaned and disinfected with chlorine gas.

Learn more about sodium chloride here;

brainly.com/question/9811771

#SPJ4

6 0

2 years ago

Choose the correct total number of electron domains (bonding and nonbonding) about a central atom if the angle(s) between the el

slamgirl [31]

Answer:

The central atom has 3 electron domains.

Explanation:

According to the Valence Shell electron pair repulsion theory (VSEPR) put forward by Gillespie and Nyholm in 1957, the shape of a molecule is determined by repulsion between all the electron pairs (electron domains) present in the valence shell.

The electron pairs or electron domains are known to position themselves as far apart in space as possible in order to minimize repulsions.

Hence, when the central atom of a molecule contains three electron domains, they are positioned at an angle of 120° from each other to minimize repulsions. Hence the answer.

5 0

3 years ago

If a lab requires each lab group to have 25ml of a solution and it takes 15 grams of CuNO3 to make 1 liter of solution how many

tino4ka555 [31]

We need to do some general algebra here.

We will find that you need 8.25 grams of CuNO₃ to make enough solution for the 22 labs.

Each lab group needs 25 ml of solution.
it takes 15 g of CuNO₃ to make one L of that solution.
There are 22 labs.

Because each lab needs 25 ml of solution, 22 labs will need that amount 22 times, so the <u>total amount of solution needed</u> is:

22*25ml = 550 ml

Now we know that we need 15 grams to make one liter of solution, and:

1 L = 1000ml

Then you need 15g to make 1000ml

and x (we want to find this amount) to make 550ml

Then we can write two equations (not actual equations, as these are different units) like:

x = 550ml

15g = 1000ml

Now we can take the quotient between these two equations:

x/15 g = (550ml/1000ml)

And now we can solve this for x:

x = (550ml/1000ml)*15g = 8.25g

So you need 8.25 grams of CuNO₃ to make enough solution for the 22 labs.

If you want to learn more, you can read:

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5 0

3 years ago