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Flauer [41]
3 years ago
7

Which of these is NOT a mixture?

Chemistry
1 answer:
TEA [102]3 years ago
7 0
The correct answer would b C
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Your aunt is sipping on iced tea and fanning herself during a hot South Carolina summer day. You tell her that there is enough e
mash [69]

Answer:

Isn't this like having enough energy to supply the world for centuries with just 1% of the sea's force?

Explanation:

I guess it's because the amount of energy in it can supply energy.

3 0
3 years ago
Why are some alkali metals stored under oil?
Dahasolnce [82]

due to there reactive rate?

6 0
3 years ago
Read 2 more answers
Now you will solve the same problem as above, but using the quadratic formula instead of iterations, to show that the same value
Dafna1 [17]

Answer:

a: 1

b: 4.5x10⁻⁴

c: 1.125x10⁻⁶

[H₃O⁺] = 0.000859M

Explanation:

As HNO₂ is a weak acid, its equilibrium in water is:

HNO₂(aq) + H₂O(l) ⇄ H₃O⁺(aq) + NO₂⁻(aq)

Equilibrium constant, ka, is defined as:

ka = 4.5x10⁻⁴ = [H₃O⁺] [NO₂⁻] / [HNO₂] <em>(1)</em>

Equilibrium concentration of each specie are:

[HNO₂] = 0.00250M - x

[H₃O⁺] = x

[NO₂⁻] = x

Replacing in (1):

4.5x10⁻⁴ = x × x / 0.00250M - x

1.125x10⁻⁶ - 4.5x10⁻⁴x = x²

0 = x² + 4.5x10⁻⁴x - 1.125x10⁻⁶

As the quadratic equation is ax² + bx + c = 0

Coefficients are:

a: 1

b: 4.5x10⁻⁴

c: 1.125x10⁻⁶

Now, solving quadratic equation:

x = -0.0013 → False answer, there is no negative concentrations.

<em>x = 0.000859</em>

As [H₃O⁺] = x; <em>[H₃O⁺] = 0.000859M</em>

I hope it helps!

6 0
3 years ago
Methanol, ethanol, and n-propanol are three common alcohols. When 1.00 g of n-propanol (C3H7OH)is burned in air, -33.4 kJ of hea
Inga [223]

Answer : The heat of combustion of n-propanol is 0.554 kJ/mol

Explanation :

First we have to calculate the moles of n-propanol.

\text{Moles of n-propanol}=\frac{\text{Mass of n-propanol}}{\text{Molar mass of n-propanol}}

Molar mass of n-propanol = 60.09 g/mole

\text{Moles of n-propanol}=\frac{1.00g}{60.09g/mole}=0.0166mole

Now we have to calculate the heat of combustion of n-propanol.

As, 0.0166 mole of n-propanol liberated heat of combustion = -33.4 kJ

So, 1 mole of n-propanol liberated heat of combustion = 0.0166 × (-33.4 kJ)

                                                                                           = 0.554 kJ/mol

Therefore, the heat of combustion of n-propanol is 0.554 kJ/mol

5 0
3 years ago
As part of an investigation into the strength of electrostatic forces between molecules of water, a student will measure the mel
Gelneren [198K]

In an experiment it is known what quantity has to measured, thus the measurement of melting point has been determining what data to collect. Thus, Option B is correct.

To investigate the boiling point of water and ethanol, the samples has to boiled at constant parameters and the data has been collected with several trials. Thus, option C is correct.

Melting has been described as the change of the solid to the liquid state. With melting, there has been heat energy higher than the force of attraction allowing the molecules to move freely. Thus, option B is correct.

The boiling has been the change in the water at liquid state to the gaseous state. With boiling there is thermal energy capable of increasing the motion of water molecules overcoming electrostatic force.

For more information about melting, refer to the link:

brainly.com/question/12499685

4 0
2 years ago
Read 2 more answers
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