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scoray [572]
3 years ago
14

True or false 12,785.000 has five significant digits.

Chemistry
2 answers:
Yuki888 [10]3 years ago
4 0

Answer:

True

Explanation:

Significant digits include non-zero digits (unless the zero is between two non-zero numbers)

In 12,785.000, there are 5 non-zero digits:

1 2 7 8 5

PSYCHO15rus [73]3 years ago
3 0

ANSWER: the answer is true.

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ollegr [7]
D) A ball sitting in a shelf
3 0
4 years ago
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Question 4(Multiple Choice Worth 4 points)
vitfil [10]

Answer:

The quantum number that describes the orientation of an orbital within a sublevel is the magnetic quantum number.

Explanation:

There are four quantum numbers in chemistry. These are the principal quantum number, the angular momentum quantum number, the magnetic quantum number, and the spin quantum number. These all follow these three foundational rules in chemistry.

The Pauli exclusion principle states that if two electrons inhabit the same orbital, they will spin in different directions.

Hund's rule states that if an orbital does not have an electron, an electron will need to fill it first before any of the other orbitals can have two electrons of differing spins.

The Aufbau principle states that all electrons will fill orbitals in an orderly fashion based on the quantum numbers.  An attachment is included of this fill order for your reference.

The four quantum numbers for chemistry are:

The principal quantum number describes the sublevel in which the orbital is located. This occurs at n = 1, 2, 3, etc. all the way to 7.

The angular momentum quantum number describes the orbital that an electron fills. It will refer to the shape and the type of orbital.  

The magnetic quantum number refers to the orientation of an orbital. Based on the angular momentum quantum number, there can be 1, 3, 5, or 7 orientations.

The spin quantum number refers to the Pauli exclusion principle. This number is assigned a negative or positive based on the orientation of the electron.

Therefore, because the magnetic quantum number is the one that refers to <u>the orientation of the orbital</u>, this is our answer.

5 0
3 years ago
In a mixture of hydrogen and nitrogen gases, the mole fraction of nitrogen is 0.333. If the partial pressure of hydrogen in the
notka56 [123]

Answer:

P_T=112.4torr

Explanation:

Hello there!

In this case, since these problems about gas mixtures are based off Dalton's law in terms of mole fraction, partial pressure and total pressure, we can write the following for hydrogen, we are given its partial pressure:

P_{H_2}=x_{H_2}*P_T

And can be solved for the total pressure as follows:

P_T=\frac{P_{H_2}}{x_{H_2}}

However, we first calculate the mole fraction of hydrogen by subtracting that of nitrogen to 1 due to:

x_{H_2}+x_{N_2}=1\\\\x_{H_2}=1-0.333=0.667

Then, we can plug in to obtain the total pressure:

P_T=\frac{75.0torr}{0.667}\\\\P_T=112.4torr

Regards!

4 0
3 years ago
What volume, in mL, of carbon dioxide gas is produced at STP by the decomposition of 0.242 g calcium carbonate (the products are
damaskus [11]

Answer:

54.21 mL.

Explanation:

We'll begin by calculating the number of mole in 0.242 g calcium carbonate, CaCO3.

This is illustrated below:

Mass of CaCO3 = 0.242 g

Molar mass of CaCO3 = 40 + 12 +(16x3) = 40+ 12 + 48 = 100 g/mol

Mole of CaCO3 =?

Mole = mass /Molar mass

Mole of CaCO3 = 0.242/100

Mole of CaCO3 = 2.42×10¯³ mole.

Next, we shall write the balanced equation for the reaction. This is given below:

CaCO3 —> CaO + CO2

From the balanced equation above,

1 mole of CaCO3 decomposed to produce 1 mole CaO and 1 mole of CO2.

Next, we shall determine the number of mole of CO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

1 mole of CaCO3 decomposed to produce 1 mole of CO2.

Therefore,

2.42×10¯³ mole of CaCO3 will also decompose to produce 2.42×10¯³ mole of CO2.

Therefore, 2.42×10¯³ mole of CO2 were obtained from the reaction.

Finally, we shall determine volume occupied by 2.42×10¯³ mole of CO2.

This can be obtained as follow:

1 mole of CO2 occupies 22400 mL at STP.

Therefore, 2.42×10¯³ mole of CO2 will occupy = 2.42×10¯³ x 22400 = 54.21 mL

Therefore, 54.21 mL of CO2 were obtained from the reaction.

7 0
3 years ago
A second unknown substance has a density of 80 g/cm and a mass of 570g. What is the volume?
Salsk061 [2.6K]

Answer:

25 g

10 cm

3

=

2.5 g/cm

3

Explanation:

6 0
3 years ago
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