Asymptote at x = 3 and a horizontal asymptote at y = 1. The curves approach these asymptotes but never cross them. The method used to find the horizontal asymptote changes depending on how the degrees of the polynomials in the numerator and denominator of the function compare.
X is the Scale factor so 18/6=X
X=3
Another way to check. the work is 6 x 3 = 18
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Answer:
(-19 , -7)
Step-by-step explanation:
y - x = 12
y + x = -25 we sum them to get
2y = -14 , y = -7
then we put -7 instead of y in any of the equations:
-7 - x = 12
-x = 19
x = -19,
finally (x , y) is (-19 , -7)
Rule needed: i^2 = -1
Standard form a + bi
(3 + 2i)(7 - 5i) FOIL
3 * 7 = 21
3 * - 5i = - 15i
2i * 7 = 14i
2i * -5i = - 10i^2 = - 10 * -1 = 10
Putting it all back together.
31 - i
