Question

Determine the number of grams of hcl that can react with 0.750 g of Al(OH)3 according to the following reaction Al(OH)₃(s)+3HCl(aq)→AlCl₃(aq)+3H₂O(aq)

Answer 1

Answer:

1040 g HCl

Explanation:

Al(OH)₃ + 3HCl => AlCl₃ + 3H₂O

moles Al(OH)₃ = 750g/78g·mol⁻¹ = 9.62 mol

moles HCl used = 3 x moles Al(OH)₃ consumed = 3(9.62)mol HCl = 1038.46 g. ≈ 1040 g HCl (3 sig.figs.)