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Sergio039 [100]
3 years ago
7

A laser beam is incident from the air at an angle of 30.00° to the vertical onto a solution of Karo syrup in water. If the beam

is refracted to 19.24° to the vertical, what is the index of refraction of the syrup solution?
Physics
1 answer:
nordsb [41]3 years ago
6 0

Answer:

1.517

Explanation:

Angle of incidence in air, i = 30°

Angle of refraction, r = 19.24°

According to the Snell's law

n = \frac{Sini}{Sinr}

Where, n be the refractive index of the syrup with respect to water. By substituting the values, we get

n = \frac{Sin30}{Sin19.24}

n = \frac{0.5}{0.3295}

n = 1.517

Thus, the refractive index of the syrup is 1.517.

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A bicyclist travels 4.5 km west, then travels 6.7 km at an angle 27.0 degrees South of West. What is the magnitude of the bicycl
Dimas [21]

Answer:

<em>10.90km</em>

Explanation:

Magnitude of the total displacement is expressed using the equation

d = √dx²+dy²

dx is the horizontal component of the displacement

dy is the vertical component of the displacement

dy = -6.7sin27°

dy = -6.7(0.4539)

dy = -3.042

For the  horizontal component of the displacement

dx = -4.5 - 6.7cos27

dx = -4.5 -5.9697

dx = -10.4697

Get the magnitude of the bicyclist's total displacement

Recall that: d = √dx²+dy²

d = √(-3.042)²+(-10.4697)²

d = √9.2538+109.6146

d = √118.8684

<em>d = 10.90km</em>

<em>Hence the magnitude of the bicyclist's total displacement is 10.90km</em>

<em></em>

6 0
3 years ago
Read the scenario.
Fofino [41]

Answer:

displacement = 2 m west

Explanation:

The displacement of an object is a vector connecting the final point of the motion of the object to the initial point, and its magnitude is equal to the length of the vector. So the magnitude of the displacement is basically the distance (measured in a straight line) between the final point and the starting point.

In this problem, we have:

- initial position of the acorn: 0 m

- final position of the acorn: 2 m west

So, the displacement has a magnitude of

d = 2 m - 0 m = 2 m

And the direction is west, since the final position is west compared to the initial position.

5 0
4 years ago
Sound waves are mechanical waves in which the particles in the medium vibrate in a direction parallel to the direction of energy
mel-nik [20]
<span>longitudinal waves

Hope this helps!</span>
6 0
3 years ago
What is the force that opposes motion and works against the downward pull? A) friction B) gravity C) weight D) acceleration
charle [14.2K]
I'm not entirely sure, but I believe it is A Friction. because gravity pulls down, weight isn't a force, and acceleration doesn't oppose motion
6 0
4 years ago
The speed of a box traveling on a horizontal friction surface changes from vi = 13 m/s to vf = 11.5 m/s in a distance of d = 8.5
ValentinkaMS [17]

The average power supplied to the box by friction while it slows from 13 m/s to 11.5 m/s is 3.24 W.

<h3>Acceleration of the box</h3>

The acceleration of the box is calculated as follows;

vf² = vi² + 2as

a = (vf² - vi²)/2s

a = (11.5² - 13²) / (2 x 8.5)

a = -2.16 m/s²

<h3>Time of motion of the box</h3>

The time taken for the box to travel is calculated as follows;

a = (vf - vi)/t

t = (vf - vi) / a

t = (11.5 - 13) / (-2.16)

t = 0.69 s

<h3>Average power supplied by the friction</h3>

P = Fv

P = (ma)(vf - vi)

P = (1 x -2.16) x (11.5 - 13)

P = 3.24 W

Thus, the average power supplied to the box by friction while it slows from 13 m/s to 11.5 m/s is 3.24 W.

Learn more about average power here: brainly.com/question/19415290

#SPJ1

7 0
2 years ago
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