Answer:
Ffriction = 90 N
coefficient = 0.3
Explanation:
First, note that the sum of all the forces in the x directions equals the mass multiplied by the acceleration in the x direction.
assuming the direction of the pulling force is positive,
243 N - Ffriction = m * a
m= 30.6 kg
a= 5 m/s/s
Ffriction= 243 - m*a
Ffriction= 243 - (30.6)(5)
Ffriction=90 N
The force of friction is equal to the coefficient of friction multiplied by the normal force on the object. Because the pulling force is completely horizontal, the normal force of the object is equal to its weight, which is m * g, or (30.6 kg)(9.8 m/s/s) = 299.88 N
Ffriction = coefficient * Fnormal
90 = coefficient * 299.88
coefficient = 0.3
