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RideAnS [48]
3 years ago
13

A Doppler blood flow unit emits ultrasound at 4.8 MHz. What is the frequency shift of the ultrasound reflected from blood moving

in an artery at a speed of 0.21 m/s?
Physics
1 answer:
Vedmedyk [2.9K]3 years ago
6 0

Answer:

1300 Hz

Explanation:

f' = Actual frequency = 4.8 MHz

f = Observed frequency

v_r = Relative velocity of blood = 0.21 m/s

v = Velocity of ultrasound = 1540 m/s

From the Doppler effect formula we have

f=f'\dfrac{v+v_r}{v-v_r}\\\Rightarrow f=4.8\dfrac{1540+0.21}{1540-0.21}\\\Rightarrow f=4.80130\ Hz

Frequency shift is given by

\Delta f=f-f'\\\Rightarrow \Delta f=4.8013-4.8\\\Rightarrow \Delta f=0.0013\ MHz=1300\ Hz

The frequency shift in the sound is 1300 Hz

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A geologist finds an area of undisturbed sedimentary rock the lowest layer is most likely the _____?
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It took 3.5 hours for a train to travel the distance between two cities at a velocity
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420

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3 years ago
A 1.50-mm-diameter glass sphere has a charge of + 1.60 nC. What speed does an electron need to orbit the sphere 1.60 mm above th
saveliy_v [14]

Answer :

Velocity will be 3.28\times 10^{-11}m/sec

Explanation:

We have given glass surface has a diameter of 1.5 mm

And charge q = 1.60 nC

Radius of electrons orbit r = height of electron above surface + radius of sphere  = =1.6+\frac{1.5}{2}=2.35mm = 0.00235m

Force on electron is given by F=\frac{1}{4\pi \epsilon _0}\frac{qe}{r^2}, here q is charge on sphere and e is charge on electron

F=\frac{1}{4\pi \epsilon _0}\frac{qe}{r^2}=\frac{kqe}{r^2}=\frac{9\times 10^9\times 1.6\times 10^{-9}\times 1.6\times 10^{-19}}{0.00235^2}=4.172\times 10^{-13}N

This force work as centripetal force

So F=\frac{mv^2}{r}

4.172\times 10^{-13}=\frac{9.11\times 10^{-31}v^2}{0.00235}

v = =0.0328\times 10^{-9}=3.28\times 10^{-11}m/sec

   

6 0
3 years ago
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