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masha68 [24]
3 years ago
12

Identify any vertical asymptotes and horizontal asymptotes? (Enter your answers as comma-separated lists of equations. If an ans

wer does not exist, enter DNE.) f(x) = −3(x + 3)(x − 2) / (x − 4)(x − 2)
Mathematics
1 answer:
salantis [7]3 years ago
4 0
(x-2) cancels from the numerator and denominator, which is called a "hole" at x = 2.
There is a vertical asymptote at x = 4.
There is a horizontal asymptote at y = -3
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Question 4 plz show ALL STEPS
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Part (a)

Locate x = -1 on the x axis. Draw a vertical line through this x value until you reach the f(x) curve. Then move horizontally until you reach the y axis. You should arrive at y = 4. Check out the diagram below to see what I mean.

Since f(-1) = 4, this means we can then say

g( f(-1) ) = g( 4 ) = 4

To evaluate g(4), we'll follow the same idea as what we did with f(x). However, we'll start at x = 4 and draw a vertical line until we reach the g(x) curve this time.

<h3>Answer:  4</h3>

==========================================================

Part (b)

We use the same idea as part (a)

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g( f(-2) ) = g(5) = 6

<h3>Answer:  6</h3>

==========================================================

Part (c)

Same idea as the last two parts. We start on the inside and work toward the outside. Keep in mind that g(x) is now the inner function for this part and for part (d) as well.

g(1) = -2

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<h3>Answer:   5</h3>

==========================================================

Part (d)

Same idea as part (c)

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