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masha68 [24]
3 years ago
12

Identify any vertical asymptotes and horizontal asymptotes? (Enter your answers as comma-separated lists of equations. If an ans

wer does not exist, enter DNE.) f(x) = −3(x + 3)(x − 2) / (x − 4)(x − 2)
Mathematics
1 answer:
salantis [7]3 years ago
4 0
(x-2) cancels from the numerator and denominator, which is called a "hole" at x = 2.
There is a vertical asymptote at x = 4.
There is a horizontal asymptote at y = -3
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What’s that simplified
bearhunter [10]

Answer:

2x^2\sqrt{5}

Step-by-step explanation:

\sqrt{20}x^2=x^2\sqrt{20}=x^2\sqrt{2*2*5}=x^2*2\sqrt{5}=2x^2\sqrt{5}

7 0
3 years ago
5t - 4 = 6 help please
Burka [1]

Answer:

t = 2

Step-by-step explanation:

5t - 4 = 6

make t the subject

move -4 to the other side of the equal sign

5t = 6 + 4

5t = 10

t = 10/5

<u>t = 2</u>

4 0
3 years ago
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Galina-37 [17]

Answer: 63

Step-by-step explanation:

3x9=27 so you would transfer that to the other equation

4 0
2 years ago
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Use the distance formula to find the distance between each pair of points round to the nearest 10th if necessary
MAXImum [283]

Given:

The pairs of points are:

a. A(-6,-4), B(-3,-1)

b. C(3.5,1), D(-4,2.5)

c. X(5,-5), Y(-5,5)

To find:

The distance between the pair of points by using the distance formula.

Solution:

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

a.

Using the distance formula, the distance between the points A(-6,-4) and B(-3,-1) is:

AB=\sqrt{(-3-(-6))^2+((-1-(-4))^2}

AB=\sqrt{(3)^2+(3)^2}

AB=\sqrt{2(3)^2}

AB=3\sqrt{2}

AB\approx 4.2

Therefore, the distance between the points A(-6,-4) and B(-3,-1) is about 4.2 units.

b.

Using the distance formula, the distance between the points C(3.5,1) and D(-4,2.5) is:

CD=\sqrt{(-4-3.5)^2+(2.5-1)^2}

CD=\sqrt{(-7.5)^2+(1.5)^2}

CD=\sqrt{56.25+2.25&#10;}

CD=\sqrt{58.5&#10;}

CD\approx 7.6

Therefore, the distance between the points C(3.5,1) and D(-4,2.5) is about 7.6 units.

c.

Using the distance formula, the distance between the points X(5,-5) and Y(-5,5) is:

XY=\sqrt{(-5-5)^2+(5-(-5))^2}

XY=\sqrt{(-10)^2+(10)^2}

XY=\sqrt{100+100}

XY=\sqrt{200}

XY\approx 14.1

Therefore, the distance between the points X(5,-5) and Y(-5,5) is about 14.1 units.

5 0
2 years ago
The equation for the line of best fit for a data set is y = 2x + 1.5. If the point (1, 4) is in the data set, what is the
ale4655 [162]

The equation for the line of best fit for a data set is y = 2x + 1.5. If the point (1, 4) is in the data set, what is the

residual of 1?

O 0.5

X 3.5

04.0

7.5

A-0.5

4 0
3 years ago
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