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barxatty [35]
3 years ago
9

A neutral atom becomes a negatively charged ion by __________ electrons

Chemistry
1 answer:
Inessa [10]3 years ago
8 0
A neutral atom becomes a negatively charged ion by accepting electrons.
For example:
F + e⁻ → F⁻
S + 2e⁻ →S²⁻
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Identify each of the following compounds as binary or ternary. Then write the chemical formula for each ionic compound.
Maurinko [17]
Binary compounds have 2 different elements, and ternary compounds have 3
Nickel(III)oxide:  binary, Ni2O3
Copper (II)iodide: binary, CuI2
Tin(IV) nitride: binary, Sn3N4
Chromium (II)bromide: binary, CrBr2
<span>Iron(III)phosphide: binary, FeP</span>
7 0
3 years ago
When methyloxirane is treated with HBr, the bromide ion attacks the less substituted position. However, when phenyloxirane is tr
konstantin123 [22]

Answer:

See explanation and picture below

Explanation:

First, in the case of methyloxirane (Also known as propilene oxide) the mechanism that is taking place there is something similar to a Sn2 mechanism. Although a Sn2 mechanism is a bimolecular substitution taking place in only step, the mechanism followed here is pretty similar after the first step.

In both cases, the H atom of the HBr goes to the oxygen in the molecule. You'll have a OH⁺ in both. However, in the case of methyloxirane the next step is a Sn2 mechanism step, the bromide ion will go to the less substitued carbon, because the methyl group is exerting a steric hindrance. Not a big one but it has a little effect there, that's why the bromide will rather go to the carbon with more hydrogens. and the final product is formed.

In the case of phenyloxirane, once the OH⁺ is formed, the next step is a Sn1 mechanism. In this case, the bond C - OH⁺ is opened on the side of the phenyl to stabilize the OH. This is because that carbon is more stable than the carbon with no phenyl. (A 3° carbon is more stable than a 2° carbon). Therefore, when this bond opens, the bromide will go there in the next step, and the final product is formed. See picture below for mechanism and products.

4 0
3 years ago
Chemistry Stoichiometry Question
Zielflug [23.3K]

The correct answer is 1.1 moles

8 0
2 years ago
Using the reaction C12H22O11 + 12 O2 -&gt;12CO2 + 11H2O (e). How many grams of carbon dioxide can be produced from 456.7g sucros
klio [65]

Answer:

704.6 g CO2

Explanation:

MM sucrose = 342.3 g/mol

MM CO2 = 44.01 g/mol

g CO2 = 456.7 g sucrose x (1 mol sucrose/MM sucrose) x (12 moles CO2/1 mol sucrose) x (MM CO2/1mol CO2) = 704.6 g CO2

7 0
2 years ago
Consider the nuclear equation below. Superscript 22 subscript 11 upper N a right arrow superscript 22 subscript 10 upper N e plu
natali 33 [55]

Answer:

+1

Explanation:

For the equation to be balanced, the total mass number and the total atomic number on both side of the equation but be equal.

This is illustrated:

For the mass number:

Left side: 22

Right side: 22 + 0 = 22

For the atomic number:

Left side: 11

Right side: 10 + x

11 = 10 + x

Collect like terms

x = 11 - 10

x = 1

See attachment for further explanation.

8 0
3 years ago
Read 2 more answers
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