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MatroZZZ [7]
3 years ago
5

Which ion has the same electron configuration as an atom of He?

Chemistry
2 answers:
pychu [463]3 years ago
6 0
It's H- since He has only 2 electron and so does H-
mariarad [96]3 years ago
3 0

Answer;

H- (negatively charged hydrogen ion)

Explanation;

The hydrogen ion has the same electron configuration as an atom of Helium. -Hydrogen ion is formed when a hydrogen atom loses or gains an electron. A positively charged ion is formed when hydrogen atom loses an electron (remaining with zero electrons) while a negatively charged ion (H-) is formed when a hydrogen atom gains an electron thus having 2 electrons.

-Helium atom has two electrons, therefore, it is similar with an negatively charged hydrogen.

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Which of the following is true about a carbonated soft drink?. . The carbon dioxide is the solvent, and water is the solute.. .
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"46.7 g of water at 80.6 oC is added to a calorimeter that contains 45.33 g of water at 40.6 oC. If the final temperature of the
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<u>Explanation:</u>

When hot water is added to the calorimeter, the amount of heat released by the hot water will be equal to the amount of heat absorbed by cold water and calorimeter.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[(m_2\times c_2)+c_3](T_{final}-T_2)       ......(1)

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m_2 = mass of cold water = 45.33 g

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T_1 = initial temperature of hot water = 80.6°C

T_2 = initial temperature of cold water = 40.6°C

c_1 = specific heat of hot water = 4.184 J/g°C

c_2 = specific heat of cold water = 4.184 J/g°C

c_3 = specific heat of calorimeter = ? J/g°C

Putting values in equation 1, we get:

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c_3=30.68J/g^oC

Hence, the specific heat of calorimeter is 30.68 J/g°C

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