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coldgirl [10]
3 years ago
13

What are the blood components?

Physics
1 answer:
Alinara [238K]3 years ago
5 0
Plasma

Red blood cells

White blood cells

Platelets

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Which letter represents the location of the<br> resister in this diagram?<br> A<br> B<br> C<br> D
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Answer:

The letter B is the letter that represents the location of the resister in the diagram.

Explanation:

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TRUE OR FALSE. if an object covers equal distance at equal intervals of time, then it is moving at constant speed and not accele
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Answer:

True

Explanation:

Speed = distance/time

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As the distance is the same (say 50m) and the time is the same (say 50s) then the speed must be the same (1m/s)

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Why does cold water sink?
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Because Any object or substance that is less dense than a fluid will float in that fluid, so hot water rises (floats) in colder water. When fluids are cooled, they contract and therefore become more dense. Any object or substance that is more dense than a fluid will sink in that fluid, so cold water sinks in warmer water
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What is the largest meteoroid that has collided with this planet
Burka [1]

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A ball thrown vertically upward is caught by the thrower after 2.00 s. Find (a) the initial velocity of the ball and (b) the max
ankoles [38]

Answer:

a)  9.8 m/s

b) 4.9 m

Explanation:

This problem is a good example of Vertical motion, where the main equations for this situation are:  

y=y_{o}+V_{o}t-\frac{1}{2}gt^{2} (1)  

V^{2}={V_{o}}^{2}-2gy (2)  

Where:  

y is the height of the ball at a given time

y_{o}=0m is the initial height of the ball (assuming the hand of the thrower the origin of the system)  

V_{o} is the initial velocity of the ball

V is the final velocity of the ball

t=2s is the time it takes for the ball to make the complete movement (from the moment it is thrown until it falls back into the pitcher's hands)

g=9.8 m/s^{2} is the acceleration due to gravity  

Knowing this, let's begin with the answers:

<h3>a) Initial velocity </h3>

In order to find the initial velocity V_{o} of the ball, we will use equation (1) and t=2s, taking into account that y=0 m and y_{o}=0m at this given time:

0=0+V_{o}t-\frac{1}{2}gt^{2} (3)  

Isolating V_{o}:

V_{o}=\frac{1}{2}gt (4)  

V_{o}=\frac{1}{2}(9.8 m/s^{2})(2 s) (5)  

Then:

V_{o}=9.8 m/s (6)  

<h3>b) Maximum height </h3>

In this part, we will use equation (2), knowing the value of the height is maximum when V=0. So, we will name this height as y_{max}:

0={V_{o}}^{2}-2gy_{max} (7)  

Isolating y_{max}:

y_{max}=\frac{{V_{o}}^{2}}{2g} (8)  

y_{max}=\frac{{(9.8 m/s)}^{2}}{2(9.8 m/s^{2})} (9)  

Finally:

y_{max}=4.9 m

4 0
4 years ago
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