Answer:
51.82
Explanation:
First of all, let's convert both vectors to cartesian coordinates:
Va = 36 < 53° = (36*cos(53), 36*sin(53))
Va = (21.67, 28.75)
Vb = 47 < 157° = (47*cos(157), 47*sin(157))
Vb = (-43.26, 18.36)
The sum of both vectors will be:
Va+Vb = (-21.59, 47.11) Now we will calculate the module of this vector:
<u>The correct option is (D). The strength of electric field depends on the amount of charge that produces the field as well as the distance from the charge. </u>
<u> </u>
Further Explanation:
The electric field intensity at a point is the measure of the force exerted by a charge particle on another charge particle in the particular area of its strength.
The electric field intensity at a distance due to a static charge having charge
is directly proportional to the amount of charge and inversely proportional to the square of the distance between them.
The Electric field intensity due to a charge is given as:
Here, is the electric field intensity,
is the amount of charge and
is the distance of the charge from the point.
The above expression of electric field shows that the electric field intensity at a point depends on the amount of charge as well as the distance of the point from the charge.
<u>Thus, the correct option is (D). The strength of electric field depends on the amount of charge that produces the field as well as the distance from the charge. </u>
<u> </u>
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Answer Details:
Grade: Senior school
Subject: Physics
Chapter: Electrostatics
Keywords: Strength, electric field, charge, distance, electric field intensity, magnitude of charge, electrostatic, test charge, kq/r^2.