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Irina-Kira [14]
3 years ago
12

An 1800-kg truck pulls a 710-kg trailer away from a stoplight with an acceleration of 1.20 m/s2 . Part A What is the net force e

xerted by the truck on the trailer? Express your answer to three significant figures and include the appropriate units. Assume that the positive x axis is directed toward the direction of motion.
Physics
1 answer:
faust18 [17]3 years ago
8 0

Answer:

F = 852 N

Explanation:

We apply Newton's second law to the trailer :

F = m*a   Formula (1)

F : net force exerted by the truck on the trailer Newtons (N)

m : mass of the trailer in kilograms (kg)

a : acceleration of the trailer in meters over second square (m/s²)

Data

a=1.20 m/s² : acceleration of the trailer

m=710 kg : mass of the trailer

We replace data in the   Formula (1)  to calculate the net force exerted by the truck on the trailer

F = (710 kg)*(1.20 m/s²)

F = 852 N

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3 years ago
If a 15 kg mass accelerates at a rate of 4 m/s2, what net force acts on it?
jarptica [38.1K]
<h2>Answer: D 60N</h2>

<h3>Explanation:</h3>

Mass(M)=15 kg

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Hope this helps

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A transformer is intended to decrease the value of the alternating current from 500 amperes to 25 amperes. The primary coil cont
EastWind [94]

Answer:

The number of turns in secondary coil is 4000

Explanation:

Given:

Current in primary coil I_{P} = 500 A

Current in secondary coil I_{S} = 25 A

Number of turns in primary coil N_{P} = 200

In case of transformer the relation between current and number of turns is given by,

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For finding number of turns in secondary coil,

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Therefore, the number of turns in secondary coil is 4000

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