Answer:
The number of turns is
Explanation:
From the question we are told that
The inner radius is
The outer radius is
The current it carries is
The magnetic field is
The distance from the center is
Generally the number of turns is mathematically represented as
Generally is the permeability of free space with value
So
Answer:
The rate of heat conduction through the layer of still air is 517.4 W
Explanation:
Given:
Thickness of the still air layer (L) = 1 mm
Area of the still air = 1 m
Temperature of the still air ( T) = 20°C
Thermal conductivity of still air (K) at 20°C = 25.87mW/mK
Rate of heat conduction (Q) = ?
To determine the rate of heat conduction through the still air, we apply the formula below.
Q = 517.4 W
Therefore, the rate of heat conduction through the layer of still air is 517.4 W