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mihalych1998 [28]
3 years ago
5

To understand the standard formula for a sinusoidal traveling wave. One formula for a wave with a y displacement (e.g., of a str

ing) traveling in the x direction is y(x,t)=Asin(kx−ωt).
All the questions in this problem refer to this formula and to the wave it describes.
1) What is the phase ϕ(x,t) of the wave? Express the phase in terms of one or more given variables ( A, k, x, t, and ω) and any needed constants like π
ϕ(x,t)=
2) What is the wavelength λ of the wave? Express the wavelength in terms of one or more given variables ( A, k, x, t, and ω) and any needed constants like π.
λ=
3) What is the period T of this wave? Express the period in terms of one or more given variables ( A, k, x, t, and ω) and any needed constants like π.
T=
4) What is the speed of propagation v of this wave? Express the speed of propagation in terms of one or more given variables ( A, k, x, t, and ω) and any needed constants like π.
v=
Physics
1 answer:
AysviL [449]3 years ago
3 0

Explanation:

The displacement of the string in the x direction is given by :

y(x,t)=A\ sin(kx-\omega t)

Where

A is the amplitude of wave

k is the propagation constant

1. Here, the phase of the wave is (kx-\omega t)

2. The propagation constant of a wave is given by :

k=\dfrac{2\pi}{\lambda}

\lambda=\dfrac{2\pi}{k}

3. Since, \omega=2\pi f

f=\dfrac{\omega}{2\pi}

Time period, T=\dfrac{1}{f}

T=\dfrac{2\pi}{\omega}

4. Speed of this wave is given by :

v=f\times \lambda

v=\dfrac{\omega}{2\pi}\times \dfrac{2\pi}{k}

v=\dfrac{\omega}{k}

Hence, this is the required solution.

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Think of the last five things you read. Now think of a type of reading you havent done recenty
GarryVolchara [31]

Answer:

1) Half Girlfriend

2) I am Malala

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4)I too had a love story

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Explanation:

I don't have a same pattern to read but mostly of romantic and fiction. I read less autobiographies but when I read I am Malala , it was an inspiring one.My favorite type of reading is romantic types and least favorite is non fiction especially History

6 0
3 years ago
How long will it take to travel 200 m traveling at 10 m/s? Follow example below.
polet [3.4K]

Answer:

variables  - d = 200m \: v = 10 m {s}^{ - 1}  \\ equation \:   - v =  \frac{d}{t}  \\ 10 = \frac{200}{t}  \\ cross \: multiply \\ 10t = 200 \\  \frac{10t}{10}  =   \frac{200}{10}  \\ t = 20s

It will take 10 seconds to travel 200m at a speed of 10m/s

Explanation:

HOPE THAT THIS IS HELPFUL.

HAVE A GREAT DAY.

4 0
2 years ago
Read 2 more answers
Consider a uniform horizontal wooden board that acts as a pedestrian bridge. The bridge has a mass of 300 kg and a length of 10
gayaneshka [121]

Answer:

F = 2123.33N

Explanation:

In order to calculate the torque applied by the left support, you take into account that the system is at equilibrium. Then, the resultant of the implied torques are zero.

\Sigma \tau=0

Next, you calculate the resultant of the torques around the right support, by taking into account that the torques are generated by the center of mass of the wooden, the person and the left support. Furthermore, you take into account that torques in a clockwise direction are negative and in counterclockwise are positive.

Then, you obtain the following formula:

-\tau_l+\tau_p+\tau_{cm}=0          (1)

τl: torque produced by the left support

τp: torque produced by the person

τcm: torque produced by the center of mass of the wooden

The torque is given by:

\tau=Fd           (2)

F: force applied

d: distance to the pivot of the torque, in this case, distance to the right support.

You replace the equation (2) into the equation (1) and take into account that the force applied by the person and the center of mass of the wood are the their weight:

-Fd_1+W_pd_2+W_{cm}d_3=0\\\\d_1=6.0m\\\\d_2=2.0m\\\\d_3=3.0m\\\\W_p=(200kg)(9.8m/s^2)=1960N\\\\W_{cm}=(300kg)(9.8m/s^2)=2940N

Where d1, d2 and d3 are distance to the right support.

You solve the equation for F and replace the values of the other parameters:

F=\frac{W_pd_2+W_d_3}{d_1}=\frac{(1960N)(2.0m)+(2940N)(3.0m)}{6.0m}\\\\F=2123.33N

The force applied by the left support is 2123.33 N

8 0
3 years ago
What's is meant by relative motion?​
saveliy_v [14]

Relative motion means a motion relative to a reference point. We can also say, relative motion means motion referred or observed from a reference point.

For example, Alex is in a train and Ace is at the station, when the train starts moving, for Ace it is moving at a speed of 10 m/s, but for Alex it is moving at 0 m/s, or we can say that it is at rest for Alex, but in motion for Ace. This is relative motion.

4 0
3 years ago
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