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mihalych1998 [28]
4 years ago
5

To understand the standard formula for a sinusoidal traveling wave. One formula for a wave with a y displacement (e.g., of a str

ing) traveling in the x direction is y(x,t)=Asin(kx−ωt).
All the questions in this problem refer to this formula and to the wave it describes.
1) What is the phase ϕ(x,t) of the wave? Express the phase in terms of one or more given variables ( A, k, x, t, and ω) and any needed constants like π
ϕ(x,t)=
2) What is the wavelength λ of the wave? Express the wavelength in terms of one or more given variables ( A, k, x, t, and ω) and any needed constants like π.
λ=
3) What is the period T of this wave? Express the period in terms of one or more given variables ( A, k, x, t, and ω) and any needed constants like π.
T=
4) What is the speed of propagation v of this wave? Express the speed of propagation in terms of one or more given variables ( A, k, x, t, and ω) and any needed constants like π.
v=
Physics
1 answer:
AysviL [449]4 years ago
3 0

Explanation:

The displacement of the string in the x direction is given by :

y(x,t)=A\ sin(kx-\omega t)

Where

A is the amplitude of wave

k is the propagation constant

1. Here, the phase of the wave is (kx-\omega t)

2. The propagation constant of a wave is given by :

k=\dfrac{2\pi}{\lambda}

\lambda=\dfrac{2\pi}{k}

3. Since, \omega=2\pi f

f=\dfrac{\omega}{2\pi}

Time period, T=\dfrac{1}{f}

T=\dfrac{2\pi}{\omega}

4. Speed of this wave is given by :

v=f\times \lambda

v=\dfrac{\omega}{2\pi}\times \dfrac{2\pi}{k}

v=\dfrac{\omega}{k}

Hence, this is the required solution.

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3 years ago
"If the object has a speed of" -2.5 m/s at x = 0m, find its speed at x = 5.00 m and its speed at x = 15.0 m.
frez [133]

Answer:

Hello your question has some missing parts attached below is the missing part

A object of mass 3.00 kg is subject to a force Fx that varies with position as in the figure below.

answer : speed at x = 5 m = 3.35 m/s

              speed at x = 15m  = 5.12 m/s

Explanation:

initial speed( x = 0 ) = 2.5 m/s

speed at x = 5.00 m = ?

speed at x = 15 m = ?

Determine speed at x = 5 m

First we will apply the expression for work-energy theorem

w = \frac{1}{2} m(v^2 - v_{0}^2 )  ----- ( 1 )

where : w = 7.50J, v_{0} = 2.5m/s , m = 3.0 kg ( in the expression of work )

input values into equation 1

7.50 = 1/2 (3 ) ( v^2 - 2.5^2 )

7.50 = 3/2 ( v^2 - 6.25 )

5 j/kg = v^2 - 6.25

∴ v = √11.25 = 3.35 m/s

Determine speed at X = 15

first we will determine the work done form x = 5 to x = 15

W = 7.5J + 15J + 7.5J = 30J,  v_{0} = 2.5m/s , m = 3.0 kg

w = \frac{1}{2} m(v^2 - v_{0}^2 ) --- ( 2 )

equation2 becomes

30J = 1/2 ( 3 ) ( v^2 - 6.25 )

30J = 3/2 ( V^2 - 6.25 )

20 J/kg = v^2 - 6.25

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3 years ago
An electron accelerates through a 12.5 V potential difference, starting from rest, and then collides with a hydrogen atom, excit
worty [1.4K]

Answer:

Explanation:

An electron accelerates through a 12.5 V potential difference, starting from rest, so it will acquire kinetic energy of 12.5 eV .

In hydrogen atom energy of n th orbit in terms of eV is given as follows

En = -13.6 / n² eV

Total energy of 1 st orbit  E₁ = - 13.6 eV

Total energy of 2 st orbit E₂ = - 13.6 eV / 2² = - 3.4 eV

Total energy of 3 st orbit E₃ = - 13.6 eV / 3² = - 1.5  eV

Total energy of 4 st orbit E₄ = - 13.6 eV / 4² = - 0.85 eV

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The electron has energy of 12,5 eV so it can excite electron from E₁ to E₃ . .

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wavelength  = 1237 / 10.2  nm = 121.27  nm

wavelength of photon possible are 651 nm , 121.27  nm , 102.23 nm .

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