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mihalych1998 [28]
3 years ago
5

To understand the standard formula for a sinusoidal traveling wave. One formula for a wave with a y displacement (e.g., of a str

ing) traveling in the x direction is y(x,t)=Asin(kx−ωt).
All the questions in this problem refer to this formula and to the wave it describes.
1) What is the phase ϕ(x,t) of the wave? Express the phase in terms of one or more given variables ( A, k, x, t, and ω) and any needed constants like π
ϕ(x,t)=
2) What is the wavelength λ of the wave? Express the wavelength in terms of one or more given variables ( A, k, x, t, and ω) and any needed constants like π.
λ=
3) What is the period T of this wave? Express the period in terms of one or more given variables ( A, k, x, t, and ω) and any needed constants like π.
T=
4) What is the speed of propagation v of this wave? Express the speed of propagation in terms of one or more given variables ( A, k, x, t, and ω) and any needed constants like π.
v=
Physics
1 answer:
AysviL [449]3 years ago
3 0

Explanation:

The displacement of the string in the x direction is given by :

y(x,t)=A\ sin(kx-\omega t)

Where

A is the amplitude of wave

k is the propagation constant

1. Here, the phase of the wave is (kx-\omega t)

2. The propagation constant of a wave is given by :

k=\dfrac{2\pi}{\lambda}

\lambda=\dfrac{2\pi}{k}

3. Since, \omega=2\pi f

f=\dfrac{\omega}{2\pi}

Time period, T=\dfrac{1}{f}

T=\dfrac{2\pi}{\omega}

4. Speed of this wave is given by :

v=f\times \lambda

v=\dfrac{\omega}{2\pi}\times \dfrac{2\pi}{k}

v=\dfrac{\omega}{k}

Hence, this is the required solution.

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3. The propeller of a World War II fighter plane is 2.30 m in diameter. (a) What is its angular velocity in radians per second i
Darya [45]

Answer:

(a) Angular velocity will be 125.6 rad/sec

(b) Linear velocity will be 144.44 m /sec

(c) Centripetal acceleration = 1849.3031 g

Explanation:

We have given diameter d = 2.30 m

So radius r = \frac{d}{2}=\frac{2.30}{2}=1.15m

(a) Speed is given as 1200 rev/min

We know that angular velocity is given by \omega =\frac{2\pi N}{60}=\frac{2\times 3.14\times 1200}{60}=125.6rad/sec

(b) Linear speed is given by v=\omega r=125.6\times 1.15=144.44m/sec

(c) Centripetal acceleration is given by a_c=\frac{v^2}{r}=\frac{144.44^2}{1.15}=18141.664m/sec^2

We know that g=9.81m/sec^2

So 18141.66m/sec^2=\frac{18141.664}{9.81}=1849.3031g

6 0
2 years ago
What is the acceleration experienced by a car that takes 10s to reach 27m/s from rest
Lerok [7]

|acceleration|  =  (change in speed) / (time for the change)

Change in the car's speed = (27 - 0) = 27 m/s
Time for the change  =  10 sec

|acceleration| = (27 m/s) / (10 s)  =  2.7 m/s² .

That's the magnitude of the car's acceleration.
We don't know anything about its direction.
5 0
3 years ago
The elements selenium and oxygen are both poor electrical conductors. In which section of the periodic table are they
murzikaleks [220]

Answer:

The answer to your question is Nonmetals

Explanation:

Nonmetals   they are bad conductors of heat and electricity except graphite.

Metalloids   they are less conductors of electricity than metals.

Noble gases  they conduct electricity.

Halogens they are not metals and do not conduct electricity.

From this information, we conclude that Oxygen and Selenium are nonmetals.

6 0
2 years ago
ANSWER FOR BRAINLIEST
Vedmedyk [2.9K]
I think the answer is A
8 0
3 years ago
A spring has a equilibrium length of 10.0 cm. When a force of 40.0 N is applied to the spring, the spring has a length of 14.0 c
mote1985 [20]

Answer:

The value of the spring constant of this spring is 1000 N/m

Explanation:

Given;

equilibrium length of the spring, L = 10.0 cm

new length of the spring, L₀ = 14 cm

applied force on the spring, F = 40 N

extension of the spring due to applied force, e = L₀ - L = 14 cm - 10 cm = 4 cm

From Hook's law

Force applied to a spring is directly proportional to the extension produced, provided the elastic limit is not exceeded.

F ∝ e

F = ke

where;

k is the spring constant

k = F / e

k = 40 / 0.04

k = 1000 N/m

Therefore, the value of the spring constant of this spring is 1000 N/m

7 0
3 years ago
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