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3 years ago

Question:

1 answer:

iogann1982 [59]3 years ago

7 0

The correct answer is:
<span>C: in the protons and neutrons of an atom

In fact, the nuclear energy refers to the binding energy of the nucleons (protons and neutrons) of an atom. The protons and the neutrons are held together by the strong nuclear interaction, one of the four fundamental forces of nature, and the energy associated to this interaction is called nuclear energy.

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Choose the true statement concerning the mass of subatomic particles.A.Electrons are more massive than protons.B.Electrons are m

Degger [83]

Answer is C. Because protons and neutrons are more massive then electrons so that means A and b and C are not right

4 0

4 years ago

Read 2 more answers

What is the unit to measure force?

melomori [17]

Answer: Newton

Explanation:

Force is measured in Newtons, which are units that equal 1 kg * m/sec2. You can calculate the amount of force that an object experiences with the equation force = mass * acceleration

5 0

3 years ago

A motorcycle is capable of accelerating at 5.1 m/s starting feom rest how far can it travel im 1.5 seconds

saul85 [17]

5.1 m/ s

~Multiply 1.5 on both sides since you’re trying to finding out how far it can travel in 1.5 seconds

5.1 x 1.5= 7.65

s x 1.5= 1.5

So a motorcycle can travel 7.65 m in 1.5 seconds.

6 0

3 years ago

The mean time between collisions for electrons in room temperature copper is 2.5 x 10-14 s. What is the electron current in a 2

Darya [45]

Answer:

1.87 A

Explanation:

τ = mean time between collisions for electrons = 2.5 x 10⁻¹⁴ s

d = diameter of copper wire = 2 mm = 2 x 10⁻³ m

Area of cross-section of copper wire is given as

A = (0.25) πd²

A = (0.25) (3.14) (2 x 10⁻³)²

A = 3.14 x 10⁻⁶ m²

E = magnitude of electric field = 0.01 V/m

e = magnitude of charge on electron = 1.6 x 10⁻¹⁹ C

m = mass of electron = 9.1 x 10⁻³¹ kg

n = number density of free electrons in copper = 8.47 x 10²² cm⁻³ = 8.47 x 10²⁸ m⁻³

$i$ = magnitude of current

magnitude of current is given as

$i = \frac{Ane^{2}\tau E}{m}$

$i = \frac{(3.14\times 10^{-6})(8.47\times 10^{28})(1.6\times 10^{-19})^{2}(2.5\times 10^{-14}) (0.01)}{(9.1\times 10^{-31})}$

$i$ = 1.87 A

4 0

3 years ago

How fast, in meters per second, does an observer need to approach a stationary sound source in order to observe a 7.1 % increase

Nutka1998 [239]

Answer:

v0 = 24.42 m/s (Approx)

Explanation:

Given:

Increase in frequency = 7.1% =

Computation:

Assume n = 100%

n1 = [(v+v0)/(v+v1)]n

[100 + 7.1] = [(344+v0)/(344+0)]100

107.1 = [(344+v0)/(344)]100

v0 = 24.42 m/s (Approx)

5 0

4 years ago