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Radda [10]
3 years ago
7

At a bargain store, Tanya bought 4 items that each cost the same amount. Tony bought 5 items that each cost the same amount, but

each was $1.25 less than the items that Tanya bought. Both Tanya and Tony paid the same amount of money. What was the individual cost of each person's items?
(a) Write an equation. Let x represent the cost of one of Tanya's items.

(b) Solve the equation. Show your work.

(c) Check your solution. Show your work.

(d) State the solution in complete sentences.
Mathematics
1 answer:
Alex_Xolod [135]3 years ago
6 0

If x is the amount that Tanya paid for each item, then Tony's items would be x-2.25. So:

3x=4(x-2.25)

3x=4x-9

x=9

x-2.25=6.75

Tanya spent $9 on each item; Tony spent $6.75 on each of his items. ☺☺☺☺

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Ilia_Sergeevich [38]

Answer:

position: (-6, -4)

range: 6

Step-by-step explanation:

The equation is that of a circle centered at (-6, -4) with a radius of √36 = 6. We presume that the "position" is that of the circle's center, and the "range" is the radius of the circle.

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The standard form equation of a circle with center (h, k) and radius r is ...

(x -h)^2 +(y -k)^2 = r^2

Matching parts of the equation, we find ...

h = -6, k = -4, r = √36 = 6.

7 0
3 years ago
Which represents the solution(s) of the graphed system of equations, y = –x2 + x + 2 and y = –x + 3?
cupoosta [38]

For this case we have the following system of equations:

y = -x ^ 2 + x + 2\\y = -x + 3

We observe that we have a quadratic equation and therefore the function is a parabola.

We have a linear equation.

Therefore, the solution to the system of equations will be the points of intersection of both functions.

When graphing both functions we have that the solution is given by:

x = 1\\y = 2

That is, the line cuts the quadratic function in the following ordered pair:

(x, y) = (1, 2)

Answer:

the solution (s) of the graphed system of equations are:

(x, y) = (1, 2)

See attached image.

3 0
3 years ago
Read 2 more answers
What is <br><img src="https://tex.z-dn.net/?f=%20%20%20cot%280.349%20%29" id="TexFormula1" title=" cot(0.349 )" alt=" cot(0.
AnnZ [28]
Cot(0.349)= 2.74804 is your answer
8 0
3 years ago
A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
AURORKA [14]

Answer:

(−0.103371 ; 0.063371) ;

No ;

( -0.0463642, 0.0063642)

Step-by-step explanation:

Shift 1:

Sample size, n1 = 30

Mean, m1 = 10.53 mm ; Standard deviation, s1 = 0.14mm

Shift 2:

Sample size, n2 = 25

Mean, m2 = 10.55 ; Standard deviation, s2 = 0.17

Mean difference ; μ1 - μ2

Zcritical at 95% confidence interval = 1.96

Using the relation :

(m1 - m2) ± Zcritical * (s1²/n1 + s2²/n2)

(10.53-10.55) ± 1.96*sqrt(0.14^2/30 + 0.17^2/25)

Lower boundary :

-0.02 - 0.0833710 = −0.103371

Upper boundary :

-0.02 + 0.0833710 = 0.063371

(−0.103371 ; 0.063371)

B.)

We cannot conclude that gasket from shift 2 are on average wider Than gasket from shift 1, since the interval contains 0.

C.)

For sample size :

n1 = 300 ; n2 = 250

(10.53-10.55) ± 1.96*sqrt(0.14^2/300 + 0.17^2/250)

Lower boundary :

-0.02 - 0.0263642 = −0.0463642

Upper boundary :

-0.02 + 0.0263642 = 0.0063642

( -0.0463642, 0.0063642)

7 0
3 years ago
Hi everyone I was wondering if someone could please help me out with this problem and explain it to me
PSYCHO15rus [73]
Join the centre O to the chord (let it be MN) & let OH be the perpendicular to the chord

OH bisects MN into 2 equal parts (each one is x/2)
OMH is a right triangle with one side =8, the second leg =x/2 & the hypotenuse = 12 (Radius)
Apply Pythagoras:

12² = 8² +(x/2)² ==>144=64 + x²/4 ==> x²=4(144-64) =320

x²=320==> x=√320 =17.88 ≈17.9



3 0
3 years ago
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