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zaharov [31]
3 years ago
15

A pebble is thrown into a calm lake, ripples are formed from the center and move outward. The water particles in the lake travel

in a circular pattern that moves up and down on the surface of a lake, and the energy travels A) diagonally. B) downward. C) horizontally. D) upward.
Physics
1 answer:
Misha Larkins [42]3 years ago
7 0

Answer: The option (C) is correct. The energy travels horizontally.

Explanation: When the pebble is thrown into a calm lake, there will be disturbance in the lake. The ripples are formed from the center and move outward because the energy is carried out from particle to particle.

The distribution of the energy among the particles starts from center and it will carry out outward. This disturbance will occur horizontally.

Therefore, the energy travels horizontally.

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A(n) ____________ image cannot be projected and forms where light rays appear to originate.
IrinaVladis [17]
A virtual image is the answer.
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You serve a volleyball with a mass of 1.4 kg. The ball leaves with a speed of 13 m/s. Calculate KE
NemiM [27]

Answer:

118.3 J

Explanation:

Givens:

m = 1.4 kg

V = 13 m/s

Formula for kinetic energy:

KE = (1/2)*(m)*(v)^2

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KE 118.3 J

J = Joules

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3 years ago
A point source emits 25.9 W of sound isotropically. A small microphone intercepts the sound in an area of 0.242 cm2, 590 m from
AnnZ [28]

The solution is in the attachment

7 0
3 years ago
ANSWER FAST!!!!
Amiraneli [1.4K]

Power = (voltage) x (current)

Power = (240 volts) x (4 Amp)

Power = 960 watts

4 0
3 years ago
I would love to stretch a wire from our house to the Shop so I can 'call' my husband in for meals. The wire could be tightened t
dezoksy [38]
Note: I'm not sure what do you mean by "weight 0.05 kg/L". I assume it means the mass per unit of length, so it should be "0.05 kg/m".

Solution:
The fundamental frequency in a standing wave is given by
f= \frac{1}{2L} \sqrt{ \frac{T}{m/L} }
where L is the length of the string, T the tension and m its mass. If  we plug the data of the problem into the equation, we find
f= \frac{1}{2 \cdot 24 m} \sqrt{ \frac{240 N}{0.05 kg/m} }=1.44 Hz

The wavelength of the standing wave is instead twice the length of the string:
\lambda=2 L= 2 \cdot 24 m=48 m

So the speed of the wave is
v=\lambda f = (48 m)(1.44 Hz)=69.1 m/s

And the time the pulse takes to reach the shop is the distance covered divided by the speed:
t= \frac{L}{v}= \frac{24 m}{69.1 m/s}=0.35 s
7 0
3 years ago
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