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yuradex [85]
3 years ago
7

A kayaker needs to paddle north across a 85 m wide harbor. The tide is going out, creating a tidal current that flows to the eas

t at 2.0 m/s. The kayaker can paddle with a speed of 3.4 m/s.
(a) In which direction should he paddle in order to travel straight across the harbor?

(b) How long will it take him to cross?
Physics
1 answer:
marshall27 [118]3 years ago
8 0

Answer:

Explanation:

Let the direction in which he peddles makes an angle of θ with north across

Sinθ = 2 / 3.4

θ = 36 degree ( west of north )

b )

component of his velocity along the north = 3.4 cos 36

= 2.75 m /s

time required = 85 / 2.75 s

= 31 s

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When an electron moves 2.5 m in the direction of an electric field, the change in electrical potential energy of the electron is
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141.78 ft

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Calculating the acceleration using one of Newton's equations of motion:

v^2 = u^2 + 2as\\\\v = 0 mi/h\\\\u = 44 mi/h\\\\s = 0.00833 mi\\\\=> 0^2 = 44^2 + 2 * a * 0.00833\\\\=> 1936 = -0.01666a\\\\a = -116206.48 mi/h^2 or -14.43 m/s^2

Note: The negative sign denotes deceleration.

When speed, v = 79mi/h, the acceleration is equal to when it is 44mi/h i.e. -116206.48 mi/h^2

Hence, we can find the minimum stopping distance using:

v^2 = u^2 + 2as\\\\v = 0 mi/h\\\\u = 79 mi/h\\\\a = -116206.48 mi/h\\\\=> 0^2 = 79^2 + (2 * -116206.48 * s)\\\\6241 = 232412.96s\\\\s = \frac{6241}{232412.96} \\\\s = 0.0268531 mi = 141.78 ft

The minimum stopping distance is 141.78 ft.

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Answer: 0 NEWTONS

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