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Scilla [17]
3 years ago
10

An astronomer would most likely use the doppler effect to question 12 options: 1) measure the color of a star. 2) measure the pa

rallax of a star. 3) measure the brightness of a star. 4) measure the shift in the emission spectrum of a star.
Physics
2 answers:
nignag [31]3 years ago
8 0

Answer:

4) measure the shift in the emission spectrum of a star.

Explanation:

Doppler effect occurs when a source emitting waves is moving relative to an observer (or when the observer is moving relative to the source). When this occurs, the frequency (and the wavelength) of the waves emitted by the source appears shifted to the observer.

In astronomy, this effect occurs with stars and galaxies. In fact, stars (and galaxies as well) move relative to us. Since stars are source of visible light (which is a form of electromagnetic radiation, so it is a form of wave), the frequency and the wavelength of the light we observe from a star is shifted. In particular, two situations are possible:

- When a star is moving away from us, its wavelength appears to be increased compared to the original wavelength: therefore, the spectrum of visible light shifts towards the red (which is the color with longer wavelength), and this is called red-shift

- When a star is moving towards us, its wavelength appears to be decreased compared to its original wavelength: therefore, the spectrum of visible light shifts towards the blue (shorter wavelength), and this is called blue-shift

zalisa [80]3 years ago
6 0

The answer would be number four. I'm sorry if I am too late. Byes.....

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Question 2
Delvig [45]

Answer:

Approximately 73\; {\rm N}, assuming that the acceleration of this ball is constant during the descent.

Explanation:

Assume that the acceleration of this ball, a, is constant during the entire descent.

Let x denote the displacement of this ball and let t denote the duration of the descent. The SUVAT equation x = (1/2)\, a\, t^{2} would apply.

Rearrange this equation to find an expression for the acceleration, a, of this ball:

\begin{aligned} a &= \frac{2\, x}{t^{2}}\end{aligned}.

Note that x = 11\; {\rm m} and t = 1.5\; {\rm s} in this question. Thus:

\begin{aligned} a &= \frac{2\, x}{t^{2}} \\ &= \frac{2 \times 11\; {\rm m}}{(1.5\; {\rm s})^{2}} \\ &\approx 9.78\; {\rm m \cdot s^{-2}}\end{aligned}.

Let m denote the mass of this ball. By Newton's Second Law of Motion, if the acceleration of this ball is a, the net external force on this ball would be m\, a.

Since m = 7.5\; {\rm kg} and a \approx 9.78\; {\rm m\cdot s^{-2}}, the net external force on this ball would be:

\begin{aligned} (\text{net force}) &= m\, a \\ &\approx 7.5\; {\rm kg} \times 9.78\; {\rm m\cdot s^{-2}} \\ &\approx 73\; {\rm kg \cdot m \cdot s^{-2} \\ &= 73\; {\rm N} && (1\; {\rm N} = 1\; {\rm kg \cdot m\cdot s^{-2}}) \end{aligned}.

4 0
2 years ago
A 174 pound Jimmy Cheek is riding on a 54 ft diameter Ferris Wheel. The normal force on Jimmy Cheek is 146 pounds when Jimmy is
Veronika [31]

To solve this problem we will apply the concepts related to the balance of Forces, the centripetal Force and Newton's second law.

I will also attach a free body diagram that allows a better understanding of the problem.

For there to be a balance between weight and normal strength, these two must be equivalent to the centripetal Force, therefore

F_c = W-N

m\omega^2r = W-N

Here,

m = Net mass

\omega= Angular velocity

r = Radius

W = Weight

N = Normal Force

m\omega^2r = 174-146

The net mass is equivalent to

F = mg \rightarrow m = \frac{F}{g}

Then,

m = \frac{174lb}{32.17ft/s^2}

Replacing we have then,

(\frac{174lb}{32.17ft/s^2})\omega^2 (54ft) =174lb-146lb

Solving to find the angular velocity we have,

\omega = 0.309rad/s

Therefore the angular velocity is 0.309rad/s

6 0
3 years ago
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