1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alekssr [168]
3 years ago
14

Neon, helium, methane, krypton, xenon, hydrogen, and ozone make up & what of the atmosphere

Physics
1 answer:
Alinara [238K]3 years ago
6 0
Part of the upper atmosphere

You might be interested in
What is the student's kinetic energy at the bottom of the hill if he is moving
soldi70 [24.7K]

Answer:

KE = 10530 J or 10.53 KJ

Explanation:

The formula for kinetic energy is KE = 1/2 mv^2

Let's apply the formula:

KE = 1/2 mv^2

KE = 1/2 (65kg) (18m/s)^2

KE = 10530 J or 10.53 KJ

5 0
3 years ago
Hunk travelled 540 km at an average speed of 90 km/h. If Tim completed the same amount of distance with 1 hour and 30 min less t
lina2011 [118]

Answer:120

Explanation:it just is trust me

8 0
3 years ago
Tarzan and Jane. Because of your concern that incorrect science is being taught to children when they watch cartoons on TV, you
creativ13 [48]

Answer:

The maximum height Tarzan and Jane can swing as a fraction of her initial heigh is ⅓h

Explanation:

Let

m = Mass of Tarzan

M = Mass of Jane

Given

M = 2m

To calculate the maximum height Tarzan and Jane can swing, we make use of the potential energy at their initial and final position.

Reason being that;

At both the initial and final position, velocity is 0, so there's no kinetic energy.

And the potential energy remains the same (i.e constant) at any given point in the system.

Using P.E = mgh.

At initial position, PE1 = mgh

At final position, PE2 = (m + M)gH.

Where h and H represent the initial and final heights.

m + M is the new weight after Jane and Tarzan swing

Equating PE1 to PE2

mgh = (m + M)gH

By substituton (M = 2m)

mgh = (m + 2m)gH

mgh = 3mgH

Make H the subject of the formula

H = mgh/3mg

H = ⅓h

Hence, the maximum height Tarzan and Jane can swing as a fraction of her initial heigh is ⅓h

From the question, the new height looks to be about ½ that of Jane's original position; i.e. ½h

The calculated height is smaller than what the cartoon is showing;

We can conclude that the cartoon is wrong.

4 0
2 years ago
A force acts on a 5kg object at rest. How fast will the object accelerate on a frictionless surface?
MakcuM [25]

Answer: The answer is C.) 25 m/s^2.

Explanation: If you input 5 as s, you would have to use the exponent 2.  This means that you have to multiply 5 by 5.  5 x 5= 25.  

Edit: Also, because the surface is frictionless, it will make the object go faster too.  Nothing can really slow it down unless something blocks it.

8 0
3 years ago
Is altitude abiotic or biotic or neither SCIENCE WORK NEEDED BY 11:59 HELP HELP HLEP
trapecia [35]

Answer:

abiotic

Explanation:

goggle:)))))))

6 0
2 years ago
Other questions:
  • Compared to the density of liquid water, the density of an ice cube is
    8·2 answers
  • A lever and fulcrum are used to lift a fallen tree, which has a weight of 480N. if the lever has a mechanical advantage of 5.5,
    5·1 answer
  • What happens if you add additional,solid NaCl after the maximum has been reached?
    8·2 answers
  • A train travels 98 kilometers in 4 hours, and then 61 kilometers in 3 hours. What is its average speed?
    11·1 answer
  • A student produces a power of p = 0.87 kw while pushing a block of mass m = 75 kg on an inclined surface making an angle of θ =
    7·1 answer
  • Which graph set-up would enable students to calculate instantaneous acceleration from the slope on the graph? a) Place distance
    15·1 answer
  • What type of device is a coal-fired power plant?
    9·1 answer
  • Which of the following is not considered a behavior?
    11·2 answers
  • Convert 5.6kg to grams
    8·2 answers
  • Question 9 of 10<br> How many carbon (C) atoms are in a molecule of CH,O?
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!