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FinnZ [79.3K]
2 years ago
15

Learning Goal: To understand the distinction between mass and weight and to be able to calculate the weight of an object from it

s mass and Newton's law of gravitation. The concepts of mass and weight are often confused. In fact, in everyday conversations, the word "weight" often replaces "mass," as in "My weight is seventy-five kilograms" or "I need to lose some weight." Of course, mass and weight are related; however, they are also very different. Mass, as you recall, is a measure of an object's inertia (ability to resist acceleration). Newton's 2nd law demonstrates the relationship among an object's mass, its acceleration, and the net force acting on it: F?net=ma?. Mass is an intrinsic property of an object and is independent of the object's location. Weight, in contrast, is defined as the force due to gravity acting on the object. That force depends on the strength of the gravitational field of the planet: W?=mg?, where W? is the weight of an object, m is the mass of that object, and g? is the local acceleration due to gravity (in other words, the strength of the gravitational field at the location of the object). Weight, unlike mass, is not an intrinsic property of the object; it is determined by both the object and its location. Which of the following quantities would be acceptable representations of weight? Check all that apply. A.) 12.0 lb B.) 0.34 g C.) 120 kg D.) 1600 kN E.) 0.34 m F.) 411 cm
Physics
1 answer:
Nimfa-mama [501]2 years ago
4 0

Answer:

The true statements are: A, D

Explanation:

This interesting problem of the conceptual relationship between mass and weight, the equation for weight is

        W = m g

From Newton's second law

       W = ma

Where g the acceleration of gravity, this acceleration can vary at several points, for example, in a vertical circumference the acceleration of gravity is always down and the centripetal acceleration continuously changes direction therefore the body weight constantly changes from zero to the maximum value.

The mass instead is always the same and is the resistance (inertia) to the movement of the bodies

Of the aforementioned the peo has the unit mass multiplied by the acceleration

           

        Weight [N] = mass [kg] acceleration [m / s2]

        Weight [lb] = mass [slug] acceleration [ft / s2]

Examine the statements

A) 12.0 lb. True pounds are the mass for acceleration. English measurement system

B) 0.34g False. Grams are units of mass,

C) 120 kg. False. The kilograms is a multiple of the grams, which are units of mass

D) 1600 kN True the newton is the unit of weight, the Newton kilo is a multiple

E) 0.34 m False meters are units of length

F) 411 cm False centimeters is a submultiple of the meter that is a unit of length

The true statements are: A, D

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30 degrees

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How many total oxygen atoms are in the compound Molybdenum (V) Dichromate?
alekssr [168]

Answer:

1.2646\times10^{25}\ atoms

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Avogadro's \ Constant=6.022\times 10^{23} \ mol_1\\\\No\ of \ Atoms=Moles\times Avogadro's \ Constant\\\\=21\times 6.022\times 10^{23} \\\\=1.2646\times10^{25}\ atoms

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3 0
3 years ago
A hollow cylinder that is rolling without slipping is given a velocity of 5.0 m/s and rolls up an incline to a vertical height o
inysia [295]

Answer:

The hollow cylinder rolled up the inclined plane by 1.91 m

Explanation:

From the principle of conservation of mechanical energy, total kinetic energy = total potential energy

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The total energy at the bottom of the inclined plane = total energy at the top of the inclined plane.

\frac{1}{2}mv_i^2 + \frac{1}{2} I \omega_i^2 + mg(0) =  \frac{1}{2}mv_f^2 + \frac{1}{2} I \omega_f^2 + mgh

moment of inertia, I, of a hollow cylinder = ¹/₂mr²

substitute for I in the equation above;

\frac{1}{2}mv_i^2 + \frac{1}{2} (\frac{1}{2}mr^2  \omega_i^2) =  \frac{1}{2}mv_f^2 + \frac{1}{2} (\frac{1}{2}mr^2  \omega_f^2) + mgh\\\\ but \ v = r \omega\\\\\frac{1}{2}mv_i^2 + \frac{1}{2} (\frac{1}{2}m v_i^2  ) =  \frac{1}{2}mv_f^2 + \frac{1}{2} (\frac{1}{2}m v_f^2) + mgh\\\\\frac{1}{2}mv_i^2 +\frac{1}{4}mv_i^2 = \frac{1}{2}mv_f^2 +\frac{1}{4}mv_f^2 +mgh\\\\\frac{3}{4}mv_i^2 = \frac{3}{4}mv_f^2 +mgh\\\\mgh = \frac{3}{4}mv_i^2 -  \frac{3}{4}mv_f^2\\\\gh = \frac{3}{4}v_i^2 -  \frac{3}{4}v_f^2\\\\

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given;

v₁ = 5.0 m/s

vf = 0

g = 9.8 m/s²

h = \frac{3}{4g}(v_1^2 -v_f^2) =\frac{3}{4*9.8}(5^2 -0) = 1.91 \ m

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5 0
2 years ago
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Answer:

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Introducing the constant of proportionality

dT(t)/dt = k[T5 - T(t)]

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4 0
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