Answer:
Work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement
Explanation:
Impulse is just the product of mass and speed!
I = 1700 * 22.5 = 38,250 kg m/s
It does not have any special name for its units :(
348.34 m/s. When Superman reaches the train, his final velocity will be 348.34 m/s.
To solve this problem, we are going to use the kinematics equations for constant aceleration. The key for this problem are the equations
and
where
is distance,
is the initial velocity,
is the final velocity,
is time, and
is aceleration.
Superman's initial velocity is
, and he will have to cover a distance d = 850m in a time t = 4.22s. Since we know
,
and
, we have to find the aceleration
in order to find
.
From the equation
we have to clear
, getting the equation as follows:
.
Substituting the values:
![a=\frac{2(850m-54.5\frac{m}{s}.4.22s) }{(4.22s)^{2}}=69.63\frac{m}{s^{2}}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B2%28850m-54.5%5Cfrac%7Bm%7D%7Bs%7D.4.22s%29%20%7D%7B%284.22s%29%5E%7B2%7D%7D%3D69.63%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D)
To find
we use the equation
.
Substituting the values:
![v_{f} =54.5\frac{m}{s} +(69.63\frac{m}{s^{2}}.4.22s)=348.34\frac{m}{s}](https://tex.z-dn.net/?f=v_%7Bf%7D%20%3D54.5%5Cfrac%7Bm%7D%7Bs%7D%20%2B%2869.63%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D.4.22s%29%3D348.34%5Cfrac%7Bm%7D%7Bs%7D)
Choice-B is the correct one.
-- The atomic number is the number of protons in the nucleus.
-- Each proton in the nucleus is usually matched by one electron in the 'cloud'.
-- The addition of a proton OR a neutron increases the mass number by 1 .
-- Electrons have such small mass that they don't figure into the atomic mass at all.
The net force on particle particle q1 is 13.06 N towards the left.
<h3>
Force on q1 due to q2</h3>
F(12) = kq₁q₂/r₂
F(12) = (9 x 10⁹ x 13 x 10⁻⁶ x 7.7 x 10⁻⁶)/(0.25²)
F(12) = -14.41 N (towards left)
<h3>Force
on q1 due to q3</h3>
F(13) = (9 x 10⁹ x 7.7 x 10⁻⁶ x 5.9 x 10⁻⁶)/(0.55²)
F(13) = 1.352 N (towards right)
<h3>Net force on q1</h3>
F(net) = 1.352 N - 14.41 N
F(net) = -13.06 N
Thus, the net force on particle particle q1 is 13.06 N towards the left.
Learn more about force here: brainly.com/question/12970081
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