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Fynjy0 [20]
3 years ago
10

If the gram-formula mass of substance X is 180 g/mol, determine the molarity of the solution at Point E

Chemistry
1 answer:
Alina [70]3 years ago
7 0
<h3><u>Answer;</u></h3>

<u>= 5 M or 5 moles/liter</u>

<h3><u>Explanation;</u></h3>

At point E, 90 g of substances X are dissolved in 100 g of the solvent.

100g of the solvent is equal to 100 ml

Molarity is the number of moles of a substance in one liter of a solvent.

90 g of X are in 100 ml

But; the RFM of X = 180 g/l

Therefore; the moles of X in 90 g = 90/180

                                                        = 0.5 moles

Therefore;

0.5 moles of X are contained in 100 ml of the solvent;

Thus, molarity = 0.5 × 1000/100

                       =<u> 5 M or 5 moles/liter</u>

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<h3>Answer:</h3>

4.70 × 10²⁴ atoms Ge

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
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<h3>Explanation:</h3>

<u>Step 1: Define</u>

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<u>Step 2: Identify Conversions</u>

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<u>Step 3: Convert</u>

\displaystyle 7.80 \ mol \ Ge(\frac{6.022 \cdot 10^{23} \ atoms \ Ge}{1 \ mol \ Ge} ) = 4.69716 × 10²⁴ atoms Ge

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

4.69716 × 10²⁴ atoms Ge ≈ 4.70 × 10²⁴ atoms Ge

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