1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
hjlf
2 years ago
8

Write the balanced equation for the equilibrium reaction for the dissociation ofsilver chloride in water, and write the K expres

sion for this reaction. Then create an ICE chart. Since we know the equilibrium concentration of the silver ion, we can solve for Ksp.Does it agree with the literature value
Chemistry
1 answer:
Marizza181 [45]2 years ago
6 0

Answer:

See explanation

Explanation:

Hello there!

In this case, since the the concentrations are not given, and not even the Ksp, we can solve this problem by setting up the chemical equation, the equilibrium constant expression and the ICE table only:

AgCl(s)\rightleftharpoons Ag^+(aq)+Cl^-(aq)

Next, the equilibrium expression according to the produced aqueous species as the solid silver chloride is not involved in there:

Ksp=[Ag^+][Cl^-]

And therefore, the ICE table, in which x stands for the molar solubility of the silver chloride:

       \ \ \ \ \ \ \ \ \ \ \ \ \ \ AgCl(s)\rightleftharpoons Ag^+(aq)+Cl^-(aq)

I          -                   0             0

C        -                   +x           +x

E        -                    x             x

Which leads to the following modified equilibrium expression:

Ksp=x^2

Unfortunately, values were not given, and they cannot be arbitrarily assigned or assumed.

Regards!

You might be interested in
Which material is an insulator against electric current?
NemiM [27]

Answer:

b) a rubber tire

Explanation:

3 0
2 years ago
Read 2 more answers
Match the compounds as organic (O) or inorganic (I).
SashulF [63]
H2O2(I)
C6H6(O)
CO2(I)
C2H6(O)
HNO3(I)
7 0
2 years ago
Read 2 more answers
What is the limiting reagent when a 2.00 g sample of ammonia is mixed with 4.00 g of oxygen?​
UNO [17]

Answer:

Ammonia is limiting reactant

Amount of oxygen left  = 0.035 mol

Explanation:

Masa of ammonia = 2.00 g

Mass of oxygen = 4.00 g

Which is limiting reactant = ?

Balance chemical equation:

4NH₃ + 3O₂     →     2N₂ + 6H₂O

Number of moles of ammonia:

Number of moles = mass/molar mass

Number of moles = 2.00 g/ 17 g/mol

Number of moles = 0.12 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 4.00 g/ 32 g/mol

Number of moles = 0.125 mol

Now we will compare the moles of ammonia and oxygen with water and nitrogen.

                      NH₃          :            N₂

                        4             :             2

                      0.12           :           2/4×0.12 = 0.06

                      NH₃         :            H₂O

                        4            :             6

                        0.12       :           6/4×0.12 = 0.18

                       

                       O₂            :            N₂

                        3             :             2

                      0.125        :           2/3×0.125 = 0.08

                        O₂           :            H₂O

                        3              :             6

                        0.125       :           6/3×0.125 = 0.25

The number of moles of water and nitrogen formed by ammonia are less thus ammonia will be limiting reactant.

Amount of oxygen left:

                        NH₃          :             O₂

                           4            :              3

                           0.12       :          3/4×0.12= 0.09

Amount of oxygen react = 0.09 mol

Amount of oxygen left  = 0.125 - 0.09 = 0.035 mol

3 0
3 years ago
How many electrons would be found in an isotope of silicon 29
kenny6666 [7]
14 electrons15 neutrons
5 0
3 years ago
N2+3H2-2NH3
NemiM [27]

102 grams of ammonia is formed when 3 moles of nitrogen and 6.7 moles of hydrogen reacts.

Explanation:

The equation given is of Haeber's process in which the nitrogen is limiting factor in the ammonia formation and hydrogen if in excess gets delimited.

We know that 1 mole of Nitrogen gives 2 moles of ammonia.

We have 3 moles of nitrogen here,

So, 6 moles of ammonia will be form

so from the formula

no of moles=mass/atomic mass

           mass= no. of moles*atomic mass

                     = 6*17

                       = 102 grams of ammonia will be formed.

So, 6 moles or 102 grams of ammonia is formed when 3 mole of nitrogen and 6.7 mole of hydrogen reacts.

7 0
3 years ago
Other questions:
  • "An increase in the price of gasoline will increase the demand for hybrid vehicles." This statement is an example of a positive
    15·1 answer
  • Word equation for Cu(s)+O2(g)=CuO(s)
    15·2 answers
  • Look at the picture​
    6·1 answer
  • How many moles of hydrogen, H2, are needed to react with 4.0 moles of nitrogen, N2
    13·1 answer
  • Need these ASAP ignore the use evidence from the text in question 1
    7·1 answer
  • Question 2 (Multiple Choice Worth 2 points)
    6·1 answer
  • The atomic number of an element is equal to the number of electrons found in an atom of that element.
    5·2 answers
  • Quantitative was to measure light intensity
    12·2 answers
  • Any expert know what is the answer?
    5·1 answer
  • Indicate the oxidation state for each of the following:
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!