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Leviafan [203]
3 years ago
6

Water is not a very good solvent. true or false

Chemistry
1 answer:
bija089 [108]3 years ago
5 0
<span>Water is not a very good solvent. FALSE</span>
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In a combustion reaction, one of the reactants is _____.
zepelin [54]
The answer is oxygen
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Which of the following would be expected to have the lowest first ionization energy?
scoundrel [369]

Explanation:

o2- Due to lowest Zeff.

I had that question and my answer was this. because you did not put options.

4 0
3 years ago
A scientist wants to react a barium chloride salt with an acid. to speed up the reaction, the scientist crushes the barium chlor
In-s [12.5K]

Out of the following given choices;

A. increasing the pH of the salt.

B. increasing the surface area of the salt.

C. increasing the pressure of the salt.

<span>D. increasing the temperature of the salt.</span>

 

The answer is B. When a substance is reduced to smaller sizes, its surface area to volume ratio increases. Therefore crushing barium salts to smaller particles increase the surface area on which it reacts with the acid. This consequently increases the rate of speed of the reaction.






6 0
3 years ago
How do you identify an electrolyte
Alex787 [66]
" if a compound is an acid or a base, but NOT one of the strong acids or bases, then it MUST be a weak electrolyte. Strong electrolytes – ionic or molecular compounds that ionize completely in solution. Weak electrolytes– molecular compounds that are partially ionized in solution."
7 0
3 years ago
1.How many milliliters of an aqueous solution of 0.157 M aluminum bromide is needed to obtain 13.4 grams of the salt?
trasher [3.6K]

Answer:

The answer to your question is:

1.- 320 ml

2.- 0.63 M

Explanation:

Data

V = ?   AlBr₃ = 0.157 M

mass = 13.4 g

Process

MW ALBr₃ = 27 + (80x3) = 267 g

                                267 g -------------------- 1 mol

                                13.4 g   ------------------  x

                                x = (13.4 x 1) / 267

                               x = 0.05 moles

Volume = 0.05/ 0.157

             = 0.320 l or 320 ml

2.-

NaNO₃ mass = 20.2 g

V = 375 ml

Molarity = ?

MW = 23 + 14 + 48 = 85g of NaNO₃

                          85 g of NaNO₃ -----------------   1 mol

                          20.2 g               -----------------   x

                         x = (20.2 x 1) / 85

                         x = 0.24 mol

Molarity = 0.24 / 0.375

             = 0.63                

4 0
3 years ago
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