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dmitriy555 [2]
3 years ago
5

What factors influence the gravitational forces between objects?

Chemistry
1 answer:
lisabon 2012 [21]3 years ago
5 0

Explanation:

F = k.m1.m2/r²

m1 and m2: masses of objects

r: distance between the objects

k: a constant

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Calculate the density of CO2 in g/cm3 at room temperature(25 degrees Celsuis) and pressure(1 atm) assuming it acts as an ideal g
Readme [11.4K]

Answer:

density=1.8x10^{-3}g/mL

Explanation:

Hello,

Considering the ideal equation of state:

PV=nRT

The moles are defined in terms of mass as follows:

n=\frac{m}{M}

Whereas M the gas' molar mass, thus:

PV=\frac{mRT}{M}

Now, since the density is defined as the quotient between the mass and the volume, we get:

P=\frac{m}{V} \frac{RT}{M}

Solving for m/V:

density= m/V=\frac{PM}{RT}

Thus, the result is given by:

density=\frac{(1atm)(44g/mol)}{[0.082atm*L/(mol*K)]*298.15K} \\density=1.8g/L=1.8x10^{-3}g/mL

Best regards.

8 0
3 years ago
Based on your solubility rules which of the following compounds would form a precipitate water?
Novosadov [1.4K]
H2SO4+NaOH=Na2SO4+H2O
3 0
3 years ago
5) Samantha added 125 mL of water to 100mL of a stock solution to make
Aleks [24]
The answer will be 3 moles
5 0
3 years ago
Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 500.
patriot [66]

Explanation:

Chemical reaction equation for the give decomposition of NH_{3} is as follows:.

          2NH_{3}(g) \rightleftharpoons N_{2}(g) + 3H_{2}(g)

And, initially only NH_{3} is present.

The given data is as follows.

  P_{NH_{3}} = 2.3 atm at equilibrium

   P_{H_{2}} = 3 \times P_{N_{2}} = 0.69 atm

Therefore,

          P_{N_{2}} = \frac{0.69 atm}{3}

                        = 0.23 aatm

So, P_{NH_{3}} = 2.3 - 2(0.23)

                       = 1.84 atm

Now, expression for K_{p} will be as follows.

         K_{p} = \frac{(P_{N_{2}})(P^{3}_{H_{2}})}{(P^{2}_{NH_{3}})}

           K_{p} = \frac{(0.23) \times (0.69)^{3}}{(1.84)^{2}}

                      = \frac{0.23 \times 0.33}{3.39}

                     = 0.0224

or,           K_{p} = 2.2 \times 10^{-2}

Thus, we can conclude that  the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture is 2.2 \times 10^{-2}.

6 0
3 years ago
As you move from row ______ to row ______ in the periodic table, the atomic radius of the elements DECREASES.
Margarita [4]

Answer:

7 to 1

Explanation:

As you move from row ----- to row ------ in the periodic table, the atomic radius of the elements DECREASES.?

And we have 7 rows in a periodic table, so the answer has to either 1 to 7 or 7 to 1

Theoretically,

Atomic size increase as we move from top to bottom as an extra shell gets added up with every period.

SO, the answer is,  7 to 1

6 0
2 years ago
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