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emmainna [20.7K]
4 years ago
9

What is the name of the phase where stars live out most of their lives?

Chemistry
1 answer:
lisov135 [29]4 years ago
8 0
The correct option is B. 
Stars live out most of their lives at MAIN SEQUENCE. Stars generally are divided into three major stages, these are:
1. Pro stars and pre-main sequence star
2. Main sequence  and giant star
3. Variable stars
Major stages in the life of a star can last for millions of years.

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What forms when copper reacts with silver nitrate?
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Answer:

solid silver and copper nitrate.

Explanation:

2AgNo3 + Cu ---- Cu(NO3)2 + 2Ag

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50 extra points and brainliest if right !!!
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Answer:

D. Two Plates are colliding.

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What is full octet composed of?​
Tems11 [23]
Answer : Eight electrons
6 0
3 years ago
PLEASE HELP!! WILL MARK BRAINLIEST!! TIME IS RUNNING OUT!!!
Juli2301 [7.4K]

<span>We can use the heat equation,
Q = mcΔT </span>

<span>

Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g</span>⁻¹ °C⁻<span>¹) and ΔT is the temperature difference (°C).</span>

 

According to the given data,

Q = 300 J 

m = 267 g

<span> c = ?
ΔT = 12 °C</span>

 

By applying the formula,

<span>300 J = 267 g x c x 12 °C
       c = 0.0936 J g</span>⁻¹ °C⁻<span>¹

Hence, specific heat of the given substance is </span>0.0936 J g⁻¹ °C⁻¹.

 


6 0
4 years ago
Vinegar is a chemical used in cooking, cleaning and other common experiences. A 0.1 M solution of vinegar in water has a [H+] of
Ymorist [56]

Answer: a) pH of a 0.1 M vinegar solution is 2.9

b) It is an acid as pH is less than 7

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

Acids have pH ranging from 1 to 6.9, bases have pH ranging from 7.1 to 14 and neutral solutions have pH equal to 7.

As vinegar is  a weak acid, its dissociation is represented as;

CH_3COOH\rightleftharpoons H^+CH-3COO^-

   cM              0             0

c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 0.1 M

[H^+]=c\times \alpha

[H^+]=0.1\times \alpha

1.3\times 10^{-3}=0.1\times \alpha

\alpha=0.013

Also pH=-log[H^+]

pH=-log[1.3\times 10^{-3}]=2.9

Thus pH of a 0.1 M vinegar solution is 2.9

As pH is less than 7,  it is an acid.

7 0
4 years ago
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