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astraxan [27]
3 years ago
15

What is the pH of a 0.1 M acid solution? a) 0 b) -1 c) 1

Chemistry
2 answers:
Alisiya [41]3 years ago
8 0

Answer:

C = 1

Explanation:

For a strong acid, equation of dissociation reaction;

HX(aq) + H2O(l) —> X- + H3O+

For a strong acid, the equilibrium reaction lies strongly to the right.

pH = -log10[H3O+] = -log10[0.1] = -(-1) = 1.

Naddik [55]3 years ago
7 0
Answer : Option C) 1

Explanation : Using the formula for finding pH of strong acid,

pH = - log_{10} [H^{+}] = -log_{10} [0.1]
= -log_{10} 10^{-1} = - (-1) = 1.

This calculation shows how to find the pH of any acid if the concentration is given.
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How many mL of 2M stock solution would I use to prepare 0.500 L of 0.1 M NaCl?
nordsb [41]

Answer:

25 mL

Explanation:

Step 1: Given data

  • Concentration of the concentrated solution (C₁): 2 M
  • Volume of the concentrated solution (V₁): ?
  • Concentration of the diluted solution (C₂): 0.1 M
  • Volume of the diluted solution (V₂): 0.500 L

Step 2: Calculate the volume of the concentrated NaCl solution

We will use the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 0.1 M × 0.500 L / 2 M

V₁ = 0.025 L = 25 mL

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3 years ago
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Hey there!

We know that a chemical reaction is balanced when there is the same amount of each element on both sides of the equation.

According to the law of conservation of mass, matter cannot be created or destroyed, so we must have the same amount of each element on each side of a chemical equation.

We count the amount of each element on each side, and the products should have the same number as the reactants.

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