Question

What is the pH of a 0.1 M acid solution? a) 0 b) -1 c) 1

Answer 1

Answer:

C = 1

Explanation:

For a strong acid, equation of dissociation reaction;

HX(aq) + H2O(l) —> X- + H3O+

For a strong acid, the equilibrium reaction lies strongly to the right.

pH = -log10[H3O+] = -log10[0.1] = -(-1) = 1.

Answer 2

Answer : Option C) 1

Explanation : Using the formula for finding pH of strong acid,

pH = - $log_{10}$ [$H^{+}$] = -$log_{10}$ [0.1]
= -$log_{10}$ $10^{-1}$ = - (-1) = 1.

This calculation shows how to find the pH of any acid if the concentration is given.