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iren2701 [21]
3 years ago
7

3.What prediction can you make about the boiling point of rubidium?

Chemistry
1 answer:
adell [148]3 years ago
8 0

Answer:

3,159°F

1,737°C

Explanation:

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What molecule contains 12.17 g of carbon, 32.53 g of sulfur, and 72.19 g of chlorine
Nina [5.8K]

The molecule is thiophosgene or CSCl₂.

<h3><u>Explanation:</u></h3>

As the informations given, the molecule contains 12.17 grams of carbon, 32.53 g of sulfur, and 72.19 g of chlorine.

Molar mass of carbon =12.

Molar mass of sulphur =32.

Molar mass of chlorine =35.

So on an average estimation, one mole of the molecule contains one mole of carbon atoms, one mole of Sulphur atoms and two moles of chlorine atoms. Molar mass of an element is the average weight of one mole of atoms of that element which is made average according to the variations of percentage availability of isotopes of that element on earth.

So the estimated molecule is CSCl₂ or thiophosgene.

8 0
3 years ago
What are some of the global effects of a volcanic eruption?​
EleoNora [17]

Answer:

<h2>People loose their homes</h2>

Explanation:

<em><u>Because of the lava that exploded, it may touch a house which may burn the house</u></em>

4 0
3 years ago
Read 2 more answers
Which option supports a theory and allows it to remain the same
mr_godi [17]

Answer:

D.

Explanation:

That would be the last option.

Repeated similar experimental outcomes are confirmation of the theory.

4 0
3 years ago
Read 2 more answers
5) When heated in a flame, the element Indium emits electromagnetic radiation with a distinctive indigo blue
grandymaker [24]

Answer:

\lambda=451nm

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve this problem by using the following equation, defined in terms of energy, Planck's constant, wavelength and speed of light:

E=\frac{hC}{\lambda }

Thus, we solve for the wavelength as shown below:

\lambda=\frac{hC}{ E}

And finally plug in the energy, Planck's constant and speed of light to obtain:

\lambda=\frac{6.6261 x 10^{-34} m^2 kg / s*3x10^8m/s}{4.405x10^{-19}m^2kg/s^2}\\\\\lambda=4.513x10^{-7}m*\frac{1nm}{10^{-9}m} \\\\\lambda=451nm

Regards!

5 0
3 years ago
I need help with chemistry!!! 20 points
cluponka [151]

Answer:

See explanation

Explanation:

5 0
3 years ago
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