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4 years ago

As shown in the figure below, a seal and the penguin are playing a fun game of tag. The penguin first swims rightward

Physics

1 answer:

RSB [31]4 years ago

7 0

Answer:

Explanation:

Average velocity = Displacement/Time

ΔS = -10+6

ΔS = -4m

Given tme = 30s

Average velocity = -4/30

Average velocity = -0.13m/s

Average speed = Distance/Time

Total distance covered = 10m+6m

Total distance covered = 16m

Average speed = 16/30

Average speed = 0.53m/s

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What does scientific theory mean

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3 years ago

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Which galaxy is the most stretched out?<br>

RideAnS [48]

Answer:

this is the anwser

Explanation:

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3 years ago

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An unknown charged particle passes without deflection through crossed electric and magnetic fields of strengths 187,500 V/m and

Kobotan [32]

Answer:

Explanation:

Given that

The electric fields of strengths E = 187,500 V/m and

and The magnetic fields of strengths B = 0.1250 T

The diameter d is 25.05 cm which is converted to 0.2505m

The radius is (d/2)

= 0.2505m / 2 = 0.12525m

The given formula to find the magnetic force is $F_{ma}=BqV---(i)$

The given formula to find the electric force is $F_{el}=qE---(ii)$

The velocity of electric field and magnetic field is said to be perpendicular

Electric field is equal to magnectic field

Equate equation (i) and equation (ii)

$Bqv=qE\\\\v=\frac{E}{B}$

$v=\frac{187500}{0.125} \\\\v=15\times10^5m/s$

It is said that the particles moves in semi circle, so we are going to consider using centripetal force

$F_{ce}=\frac{mv^2}{r}---(iii)$

magnectic field is equal to centripetal force

Lets equate equation (i) and (iii)

$Bqr=\frac{mv^2}{r} \\\\\frac{q}{m}=\frac{v}{Br} \\\\\frac{q}{m} =\frac{15\times 10^5}{0.125\times0.12525} \\\\=\frac{15\times10^5}{0.015656} \\\\=95808383.23\\\\=958.1\times10^5C/kg$