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Aleksandr-060686 [28]
3 years ago
8

You are driving home from school steadily at 95 km/h for 130 km. During raining, you begin to

Physics
1 answer:
Svetradugi [14.3K]3 years ago
8 0
We have 2 journeys , one to school and one to home.
We already have the distance travelled in the first journey .
To find the distance of the second one , we need to find out the time .

Because ,
D= Time x speed
Since have the distance of the first journey , we can find the the time of the second journey .

Using the formula:
Time= D/S

To find the total time :

First:
Convert 20 minutes to hours : 20/60= 0.33 hrs
And add it to 3 (3hrs) = 3+0.33= 3.33hrs

This is our total time .


Second:
To find the time of the first journey , we divide:
130/95= 1.36hrs
(D/S)=T

Since we need the time of the second half, we subtract the time of the first half from the total time travelled:
3.33-1.36= 1.97hrs

And that’s how we found out the time of the second journey (again to find distance).

Now , the last step is to workout the distance travelled at the second journey.
We have the time = 1.97 hrs and the speed = 65 km/h
D=T x S
1.97 x 65= 128.05 km

And that’s your answer.



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You are loading a refrigerator weighing 2267 N onto a truck, using a wheeled cart. The refrigerator is raised 1.09 m to the truc
meriva

Answer:

a).

Wmin= 2471.03 J

W=1603.01 J

Explanation:

Weight, w= 2267 N

w= m*g\\W=m*g*h \\W=w*h

Minimum work 'h' is the distance the refrigerator is raised h=1.09m

W_{min}=2267 N* 1.09m\\W_{min}=2471.03 J

The motion is no frictional force so, the magnitude of the force with a angle of 45.0° is find using:

W=m*g*h'\\h'= sin(45)\\W=2267N*sin(45)\\W=1603.01 J

6 0
3 years ago
A net force of 10.0 N causes an object to accelerate at 2.00m/s^2. What is the mass of the object?
madam [21]

5.00kg

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4 0
3 years ago
A lawyer drives from her​ home, located 1 mile east and 8 miles north of the town​ courthouse, to her​ office, located 4 miles w
givi [52]

Answer:

d = 13 miles

Explanation:

Lets say the position of court house is origin in this case

her office is located at 4 miles west and 4 miles south of court house

so here we have coordinate of the office with respect to court house is given as

r_1 = (-4\hat i - 4\hat j)

now the position of her home is located at 1 miles east and 8 miles north of the court house

so the coordinates of her home is given as

r_2 = (1\hat i + 8 \hat j)

now the change in the position is given as the distance between office and home

d = r_2 - r_1

d = 5 \hat i + 12 \hat j

d = \sqrt{5^2 + 12^2} = 13 miles

4 0
3 years ago
A train travels at a speed of 30 m/s. The train starts at an initial position of 1000 meters and travels for 30 seconds. What is
pychu [463]
1000 + 30x30 = 1900. Hope that helps
6 0
3 years ago
At a distance of 0.208 cm from the center of a charged conducting sphere with radius 0.100cm, the electric field is 485 n/c . wh
Anna35 [415]

We have the equation for electric field E = kQ/d^{2}

Where k is a constant, Q is the charge of source and d is the distance from center.

In this case E is inversely proportional to d^{2}

So, \frac{E_{1} }{E_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}

E_{1} = 485 N/C

d_{1} = 0.208 cm

d_{2} = 0.620 cm

E_{2} = ?

\frac{485 }{E_{2}} = \frac{0.620^{2}}{0.208^{2}}

E_{2} = \frac{485*0.208^{2}}{0.628^{2}}

E_{2} = 53.20 N/C

7 0
3 years ago
Read 2 more answers
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