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Aleksandr-060686 [28]
3 years ago
8

You are driving home from school steadily at 95 km/h for 130 km. During raining, you begin to

Physics
1 answer:
Svetradugi [14.3K]3 years ago
8 0
We have 2 journeys , one to school and one to home.
We already have the distance travelled in the first journey .
To find the distance of the second one , we need to find out the time .

Because ,
D= Time x speed
Since have the distance of the first journey , we can find the the time of the second journey .

Using the formula:
Time= D/S

To find the total time :

First:
Convert 20 minutes to hours : 20/60= 0.33 hrs
And add it to 3 (3hrs) = 3+0.33= 3.33hrs

This is our total time .


Second:
To find the time of the first journey , we divide:
130/95= 1.36hrs
(D/S)=T

Since we need the time of the second half, we subtract the time of the first half from the total time travelled:
3.33-1.36= 1.97hrs

And that’s how we found out the time of the second journey (again to find distance).

Now , the last step is to workout the distance travelled at the second journey.
We have the time = 1.97 hrs and the speed = 65 km/h
D=T x S
1.97 x 65= 128.05 km

And that’s your answer.



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Answer:

EMF = 33880 Volts

Explanation:

As per Faraday's law of Electromagnetic induction we know that

Rate of change in magnetic flux will induce EMF in the closed conducting loop

so we have

\phi = B.A

now we have

A = (110 \times 10^3)(110 \times 10^3)

A = 1.21 \times 10^{10}

now we have

\phi = B(1.21 \times 10^{10})

now the induced EMF through this loop is given as

EMF = (\frac{dB}{dt})(1.21 \times 10^{10})

EMF = (2.8 \times 10^{-6})(1.21 \times 10^{10})

EMF = 33880 Volts

5 0
3 years ago
Which of the following statements about electromagnetic radiation it true? A.electromagnetic waves with long wavelength are more
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Answer:

Electromagnetic radiation is an electric and magnetic disturbance traveling through space at the speed of light (2.998 × 108 m/s). It contains neither mass nor charge but travels in packets of radiant energy called photons, or quanta.

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2 years ago
Jake is in chemistry class. He makes a list of the chemicals his instructor described and the properties of each.
koban [17]
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Read 2 more answers
A dielectric-filled parallel-plate capacitor has plate area A = 30.0 cm2 , plate separation d = 9.00 mm and dielectric constant
PIT_PIT [208]

Answer:

9.96\cdot 10^{-10}J

Explanation:

The capacitance of the parallel-plate capacitor is given by

C=\epsilon_0 k \frac{A}{d}

where

ϵ0 = 8.85x10-12 C2/N.m2 is the vacuum permittivity

k = 3.00 is the dielectric constant

A=30.0 cm^2 = 30.0\cdot 10^{-4}m^2 is the area of the plates

d = 9.00 mm = 0.009 m is the separation between the plates

Substituting,

C=(8.85\cdot 10^{-12}F/m)(3.00 ) \frac{30.0\cdot 10^{-4} m^2}{0.009 m}=8.85\cdot 10^{-12} F

Now we can calculate the energy of the capacitor, given by:

U=\frac{1}{2}CV^2

where

C is the capacitance

V = 15.0 V is the potential difference

Substituting,

U=\frac{1}{2}(8.85\cdot 10^{-12}F)(15.0 V)^2=9.96\cdot 10^{-10}J

4 0
3 years ago
a projectile is shot horizontally from the edge of a cliff, 230m above the ground. the projectile lands 300m from base of the cl
bekas [8.4K]

Answer:

The time taken by the projectile to hit the ground is 6.85 sec.

Explanation:

Given that,

Vertical height of cliff = 230 m

Distance = 300 m

Suppose, determine the time taken by the projectile to hit the ground.

We need to calculate the time

Using second equation of motion

s=ut+\dfrac{1}{2}gt^2

Where, s = vertical height of cliff

u = initial vertical velocity

g = acceleration due to gravity

Put the value in the equation

230=0+\dfrac{1}{2}\times9.8\times t^2

t=\sqrt{\dfrac{230\times2}{9.8}}

t=6.85 sec

Hence, The time taken by the projectile to hit the ground is 6.85 sec.

7 0
3 years ago
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