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3 years ago

Two astronauts of mass 100 kg are 2 m apart in outer space. What is the

Physics

2 answers:

fredd [130]3 years ago

4 0

The force of gravity between the astronauts is $1.67\cdot 10^{-7}N$

Explanation:

The magnitude of the gravitational force between two objects is given by:

$F=G\frac{m_1 m_2}{r^2}$

where :

$G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}$ is the gravitational constant

$m_1, m_2$ are the masses of the two objects

r is the separation between them

In this problem, we have two astronauts, whose masses are:

$m_1 = 100 kg\\m_2 = 100 kg$

While the separation between the astronauts is

r = 2 m

Substituting into the equation, we can find the gravitational force between the two astronauts:

$F=\frac{(6.67\cdot 10^{-11})(100)(100)}{2^2}=1.67\cdot 10^{-7}N$

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

san4es73 [151]3 years ago

4 0

Answer:

1.67*10^-7 N

Explanation:

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2 years ago

A thin flake of mica (n=1.58) is used to cover one slit of a double-slit interference arrangement. The central point on the wiew

Llana [10]

To develop this problem it is necessary to apply the optical concepts related to the phase difference between two or more materials.

By definition we know that the phase between two light waves that are traveling on different materials (in this case also two) is given by the equation

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Where

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Our values are given as

$\Phi = 7(2\pi)$

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Replacing our values at the previous equation we have

$\Phi = 2\pi(\frac{L}{\lambda}(n_1-n_2))$

$7(2\pi) = 2\pi(\frac{t}{\lambda}(1.58-1))$

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3 years ago

how do I solve how much time does it take for a satellite moving 15000 miles per hour travel to travel once around the earth 249

iogann1982 [59]

Answer:

The time taken by the satellite to orbit earth at its surface, t = 1.66 hr

Explanation:

Given data,

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3 years ago