A force of 500 N is exerted on a baseball by the bat for 0.001 s. What is the change in momentum of the baseball?

If you are watching TV programs from 3::50AM-5:30AM for how much hour you are watching

Triss [41]

Answer:

1 hour and 40 mins

Explanation:

6 0

3 years ago

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If you hit another object with your vehicle, your _______ will be slowed or stopped by the force of impact caused by that object

BaLLatris [955]

Answer:

Speed

Explanation:

If a vehicle hit any other object then its speed will slow down or some time the vehicle will stop its depends on the force exerted by other object on the vehicle.

The change in speed of vehicle is due to momentum because momentum is always conserved. So to conserve the momentum the speed of the vehicle decreases because after hitting the overall mass is increases.

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3 years ago

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A major league baseball pitcher throws a pitch that follows these parametric equations: x(t) = 142t y(t) = –16t2 + 5t + 5. The t

azamat

Answer:

(a) $x'(t)= 142$

(b) 142

(c) $y'(t)= -32t+5$

(d) 96.8 mph

(e) 0.426 s

(f) 0.061 rad

Explanation:

Velocity is a time-derivative of position.

(a) $x(t) = 142t$

$x'(t)= 142$

(b) Since $x'(t)= 142$ is independent of $t$ , it follows it was constant throughout. Hence, at any point or time, the horizontal velocity is 142.

(c) $y(t) = - 16t^2+5t+5$

$y'(t)= -32t+5$

(d) When it passes the home plate, the ball has travelled 60.5 ft (from the question). This is horizontal, so it is equivalent to $x(t)$ .

$x(t)= 142t = 60.5$

$t=\dfrac{60.5}{142}= 0.426$ .

In this time, the vertical velocity, $y'(t)$ is

$y(t)= -32\times0.426+5 = -8.632$

The speed of the ball at thus point is $s=\sqrt{142^2+(-8.632)^2}=142$ ft/s

To convert this to mph, we multiply the factor 3600/5280

$s=142\times\dfrac{3600}{5280}=96.8 \text{ mph}$

(e) The time has been determined from (d) above.

$t= 0.426$

(f) This angle is given by

$\theta=\tan^{-1}\dfrac{y'(t)}{x'(t)}$

$\theta=\tan^{-1}\dfrac{-8.632}{142}=\tan^{-1}-0.0607=3.47$ (Note here we are considering the acute angle so we ignore the negative sign)

In radians, this is

$\theta=3.47\times\dfrac{\pi}{180}=0.061 \text{ rad}$

6 0

4 years ago

A 75.0 kg object decelerates from a speed of 100 m/s to 50 m/s over an interval of 25 seconds. What was the net force acting upo

lukranit [14]

Assuming constant acceleration a, the object has undergoes an acceleration of

a = (50 m/s - 100 m/s) / (25 s) = -2 m/s²

Then the net force has a magnitude F such that, by Newton's second law,

F = (75.0 kg) a

F = (75.0 kg) (-2 m/s²)

F = -150 N

meaning the object is acted upon by a net force of 150 N in the direction opposite the initial direction in which the object is moving.

7 0

3 years ago

While taking the stairs it takes you 10 seconds to reach the top. The next time you take the same stairs, it takes you 5 seconds

Ksju [112]

Answer:

P₂ = 2 P₁

we conclude that in the second time the power used is double that in the first rise

Explanation:

In this exercise we are asked the power to climb the stairs, if we assume that we go up with constant speed, we use an energy equal to the potential energy due to the difference in height of the stairs, as this height is constant the potential energy does not change and therefore therefore the energy used by us does not change either.

Now we can analyze the required power,

P = W / t

From the analysis of the previous paragraph the work is equal to the energy used, according to the work energy theorem,

therefore the first time the power is

P₁ = E / 10

P₁ = 0.1 E

for the second time the power is

P₂ = E / 5

P₂ = 0.2 E

we see that the power in the second case is

P₂ = 2 P₁

Therefore, we conclude that in the second time the power used is double that in the first rise.

6 0

3 years ago