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kirza4 [7]
2 years ago
5

Sometimes referred to as the law of inertia. An object at rest stays at rest and an object in motionstays in motion with the sam

e speed and in the same direction unless acted upon by an unbalanced force.
A Unbalanced force
B Newton's Second Law of Motion
С Newton's Third Law of Motion
D Newton's First Law of Motion​
Physics
1 answer:
Lera25 [3.4K]2 years ago
5 0

Answer:

D

Explanation:

Newtons first law states that if an object is at rest it will stay at rest only if an unbalanced force acts on it. As well as if an object is in motion it will stay in motion unless an unbalanced force acts on it.

Ps- The object will stay moving in the same speed and direction.

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A mass of 2000 kg. is raised 5.0 m in 10 seconds. What is the potential energy of the mass at this height?
kolbaska11 [484]

Answer:

98,000J

Explanation:

Given parameters :

Mass = 2000kg

Height = 5m

Time = 10s

P. E = mgh

P. E = 2000x 5x 9.8

P.E = 98,000J

5 0
2 years ago
An object has a mass of 7g and a volume of 14cm. What is the density
Andreyy89
Density = mass / volume = 7/14 = 0.5!g/cm^3
8 0
3 years ago
On a cross-country trip, a couple drives 500 mi in 10 h on the first day, 380 mi in 8.0 h on the second day, and 600 mi in 15 h
Zepler [3.9K]

We know that the average speed is simply the ratio of the total distance travelled over the total duration of the trip.

total distance = 500 mi + 380 mi + 600 mi

total distance = 1,480 mi

 

total time = 10 h + 8 h + 15 h

total time = 33 h

 

So the average speed is therefore:

average speed = 1,480 mi / 33 h

<span>average speed = 44.85 mi / h</span>

8 0
3 years ago
In a compound microscope, the objective has a focal length of 1.0 cm, the eyepiece has a focal length of 2.0 cm, and the tube le
expeople1 [14]

Answer:

The  value  is   m \approx   310

Explanation:

From the question we are told that

     The  focal length of the objective is  f_o =  1.0 \ cm

    The  focal length of the eyepiece is  f_e  =  2.0 \  cm

    The  tube length is  L  =  25 \  cm

Generally the magnitude of the overall magnification is mathematically represented as

            m =  m_o  *  m_e

Where  m_o is the objective magnification which is mathematically represented as

        m_o  =  \frac{L}{f_o }

=>      m_o  =  \frac{25}{1 }

=>      m_o  =  25

m_e is the eyepiece magnification which is mathematically evaluated as

     m_e  =  \frac{L }{f_e }

     m_e  =  \frac{25 }{ 2}

      m_e  =  12.5 \  cm

So

    m =  25 * 12.5

     m \approx   310

6 0
3 years ago
HELP!!!!!
devlian [24]

Answer:

c

Explanation:

6 0
3 years ago
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